BigQuery - 將數組中的元素添加到結構數組中

Question

我有一個看起來像這樣的結構：

{"event": {
    "timestamp": [        
        "2019-01-13 17:21:08.570140 UTC",
        "2019-01-14 14:10:55.475515 UTC",
        "2019-01-09 14:02:51.848917 UTC"
    ],
    "properties": [
        {"device_model": "iPhone", "country": "United Kingdom"},
        {"device_model": "Android", "country": "United States"},
        {"device_model": "iPhone", "country": "Sweden"}
    ]
}

我想實現這一點：讓每個時間戳進入相應的結構。

{"event": [
        {"timestamp": "2019-01-13 17:21:08.570140 UTC","device_model": 
         "iPhone", "country": "United Kingdom"},
        {"timestamp": "2019-01-14 14:10:55.475515 UTC", "device_model": 
         "Android", "country": "United States"},
        {"timestamp": "2019-01-09 14:02:51.848917 UTC", "device_model": 
         "iPhone", "country": "Sweden"}
    ]
}

我從這樣的查詢創建了當前結構：

WITH
  events AS (
  SELECT
    "customer_1" AS customer_id,
    "timestamp_1" AS timestamp,
    STRUCT("iphone" AS device_model,
      "uk" AS country ) AS properties
  UNION ALL
  SELECT
    "customer_2" AS customer_id,
    "timestamp_2" AS timestamp,
    STRUCT("android" AS device_model,
      "us" AS country) AS properties
  UNION ALL
  SELECT
    "customer_2" AS customer_id,
    "timestamp_3" AS timestamp,
    STRUCT("iphone" AS device_model,
      "sweden" AS country) AS properties )
SELECT
  customer_id,
  STRUCT(ARRAY_AGG(timestamp) AS timestamp,
    ARRAY_AGG(properties) AS properties) AS event
FROM
  events
GROUP BY
  customer_id

如何修改查詢以獲得所需的結構？

- - 編輯

我可以這樣做，但這需要在我生成查詢時知道屬性的模式 - 這是可能的，但不是很漂亮。 有沒有更簡單的方法？

WITH
  events AS (
  SELECT
    "customer_1" AS customer_id,
    "timestamp_1" AS timestamp,
    STRUCT("iphone" AS device_model,
      "uk" AS country ) AS properties
  UNION ALL
  SELECT
    "customer_2" AS customer_id,
    "timestamp_2" AS timestamp,
    STRUCT("android" AS device_model,
      "us" AS country) AS properties
  UNION ALL
  SELECT
    "customer_2" AS customer_id,
    "timestamp_3" AS timestamp,
    STRUCT("iphone" AS device_model,
      "sweden" AS country) AS properties )
SELECT
  customer_id,
  ARRAY_AGG(properties) AS event
FROM (
  SELECT
    customer_id,
    struct(timestamp as timestamp, 
           properties.device_model as device_model, 
           properties.country as country) as properties
  FROM
    events)
GROUP BY
  customer_id

Answer 1

您可以利用SELECT AS STRUCT並使用properties作為選擇器來做這樣的事情。

SELECT
  customer_id,
  ARRAY_AGG(properties) AS prop
FROM (
  SELECT
    customer_id,
    (
    SELECT
      AS STRUCT timestamp,
      properties.*) AS properties
  FROM
    events e )
GROUP BY
  1

這將返回：

[
  {
    "customer_id": "customer_1",
    "prop": [
      {
        "timestamp": "timestamp_1",
        "device_model": "iphone",
        "country": "uk"
      }
    ]
  },
  {
    "customer_id": "customer_2",
    "prop": [
      {
        "timestamp": "timestamp_2",
        "device_model": "android",
        "country": "us"
      },
      {
        "timestamp": "timestamp_3",
        "device_model": "iphone",
        "country": "sweden"
      }
    ]
  }
]

你可以進一步寫下這樣的文章：

SELECT AS STRUCT e.* except(customer_id)