從與嵌套在對象中的對象的key：value對匹配的數組中返回對象，我需要返回

Question

期望狀態

我試圖從匹配特定值的數組中返回一個對象，但是由於該數組包含嵌套在另一個對象中的對象，因此我遇到了一些問題。 我想返回整個對象，但是我需要搜索的值是在嵌套對象內部。

例如，我試圖基於key：value對“ name”：“ Kills”的值返回整個對象。

 {
    "metadata": {
        "key": "kills",
        "name": "Kills",
        "isReversed": false
    },
    "value": 1364,
    "displayValue": "1,364"
}

數組格式

let stats = [
            {
                "metadata": {
                    "key": "kills",
                    "name": "Kills",
                    "isReversed": false
                },
                "value": 1364,
                "displayValue": "1,364"
            },
            {
                "metadata": {
                    "key": "score",
                    "name": "Score",
                    "isReversed": false
                },
                "value": 413743,
                "displayValue": "413,743"
            },
            {
                "metadata": {
                    "key": "matchesPlayed",
                    "name": "Matches Played",
                    "isReversed": false
                },
                "value": 2160,
                "displayValue": "2,160"
            }

        ]

當前代碼無效

我不打算使用這種結構的代碼，任何可行的解決方案對我來說都是很棒的，但我需要它成為可以重用的功能。

function getStatsFields(value, statsSegment){
  console.log('getStatsFields ran', statsSegment.stats[0].metadata.name);

  console.log('statsSegment.stats.length', statsSegment.stats.length);
  var filteredStats = []
  for(var i=0; i < statsSegment.stats.length; ++i){
    const killsKey = Object.keys(statsSegment.stats[i].metadata.name)
    console.log('killsKey', killsKey);
    filteredStats = statsSegment.stats.filter(val => val[killsKey] === value)
    console.log('filteredStats before if', filteredStats);
    if(filteredStats.length){
      console.log('filteredStats[i]', filteredStats[i]);

      return filteredStats[i];
    }
  }

}

任何幫助將不勝感激！

Answer 1

嘗試

stats.find(x=> x.metadata.name=="Kills");

 let stats= [ { "metadata": { "key": "kills", "name": "Kills", "isReversed": false }, "value": 1364, "displayValue": "1,364" }, { "metadata": { "key": "score", "name": "Score", "isReversed": false }, "value": 413743, "displayValue": "413,743" }, { "metadata": { "key": "matchesPlayed", "name": "Matches Played", "isReversed": false }, "value": 2160, "displayValue": "2,160" } ] let r= stats.find(x=> x.metadata.name=="Kills"); console.log(r); 

Answer 2

如果您正在尋找一種根據元數據（ key ， value ）對進行過濾的方法，那么下一個可以幫助您：

 const stats = [ { "metadata": { "key": "kills", "name": "Kills", "isReversed": false }, "value": 1364, "displayValue": "1,364" }, { "metadata": { "key": "score", "name": "Score", "isReversed": false }, "value": 413743, "displayValue": "413,743" }, { "metadata": { "key": "matchesPlayed", "name": "Matches Played", "isReversed": false }, "value": 2160, "displayValue": "2,160" } ]; const filterByMetaKeyVal = (arr, metakey, v) => { return arr.filter(({metadata}) => metadata[metakey] === v); } console.log( "Filter by [name, Kills]:", filterByMetaKeyVal(stats, "name", "Kills") ); console.log( "Filter by [key, matchesPlayed]:", filterByMetaKeyVal(stats, "key", "matchesPlayed") ); console.log( "Filter by [isReversed, true]:", filterByMetaKeyVal(stats, "isReversed", true) ); 

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