[英]How to make a function that contains a promise return a value instead of a promise?
[英]How to make a function return a promise
我想在調用此函數時返回downloadURL
,它是一個firebase上傳函數。
import { storage } from "./base"; import firebase from "firebase"; function uploadFile(file, metadata) { return new Promise((resolve, reject) => { const task = storage.child(`/${file.name}`).put(file, metadata); task.on( firebase.storage.TaskEvent.STATE_CHANGED, function(snapshot) { var progress = (snapshot.bytesTransferred / snapshot.totalBytes) * 100; console.log(progress); }, function(error) { switch (error.code) { case "storage/unauthorized": break; case "storage/canceled": break; case "storage/unknown": break; default: break; } reject(error); }, function() { task.snapshot.ref.getDownloadURL().then(function(downloadURL) { resolve(downloadURL); console.log(downloadURL); }); }, ); }); } export { uploadFile };
我試過了,它沒有返回downloadURL
您可以簡單地嘗試如下操作:
在promise中使用then
方法來獲取已解決的downloadUrl
uploddFile(file, data).then(downloadUrl => console.log(downloadUrl) );
嘗試這個。
import { storage } from "./base";
import firebase from "firebase";
function uploadFile(file, metadata) {
return new Promise((resolve, reject) => {
const task = storage.child(`/${file.name}`).put(file, metadata);
task.on(
firebase.storage.TaskEvent.STATE_CHANGED,
function(snapshot) {
var progress = (snapshot.bytesTransferred / snapshot.totalBytes) * 100;
console.log(progress);
},
function(error) {
switch (error.code) {
case "storage/unauthorized":
break;
case "storage/canceled":
break;
case "storage/unknown":
break;
default:
break;
}
reject(error);
},
task.snapshot.ref.getDownloadURL().then(function(downloadURL) {
resolve(downloadURL);
console.log(downloadURL);
});
,
);
});
}
想法是,一旦成功完成getDownloadURL,便包括resolve方法。 然后可以通過調用上面的答案中提到的來檢索
uploadFile(file, metaData)
.then((download) => console.log(downloadURL)) ; // Or whatever you want to do wth downloadURL
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