查找所有可能的數字組合以獲得給定的總和 - Python 到 Nodejs

Question

有人可以幫我將此代碼轉換為 nodejs 嗎？

def subset_sum(numbers, target, partial=[], partial_sum=0):

    if partial_sum == target:
        #print("partial_sum")
        #print(target)
        yield partial
    if partial_sum >= target:
        return

    #print(*enumerate(numbers))
    print(*partial)
    for i, n in enumerate(numbers):
        #print(i)
        remaining = numbers[i + 1:]

        yield from subset_sum(remaining, target, partial + [n], partial_sum + n)



list(subset_sum([1, 2, 3, 7, 7, 9, 10], 10))

Answer 1

如果您實現自己的enumerate函數，那么對現代 js 的轉換確實幾乎是 1:1。

 console.log(Array.from(subsetSum([1, 2, 3, 7, 7, 9, 10], 10))) function* subsetSum(numbers, target, partial = [], partialSum = 0) { if (partialSum === target) yield partial if (partialSum >= target) return for(const [i, n] of enumerate(numbers)) { yield* subsetSum(numbers.slice(i + 1), target, [...partial, n], partialSum + n) } } function* enumerate(iterable) { let i = 0 for(const item of iterable) { yield [i++, item] } }