在 Python 的 for 循環中檢查 2 個不同的用戶輸入

Question

我對此很陌生，並試圖循環遍歷一系列數字，直到 2 個不同的用戶對特定數字說“是”。

如果兩個用戶都對一個數字說是，我希望程序打印“你們都選擇了 [X]！” X 是數字，循環在此時停止。

但是，如果任一用戶拒絕，我希望循環簡單地繼續到下一個數字。 為什么下面的代碼不能實現這一目標？

for i in range(100):
    user1_response = input("User One: Would you like to pick " + str(i) + "? ")
    user2_response = input("User Two: Would you like to pick " + str(i) + "? ")

    if (user1_response == "N" or "No" or "Reject") or (user2_response == "No" or "N" or "Reject"):
        continue

    else:
        print("")
        print("Both users picked" + str(i) + "!")
        break

Answer 1

 if (user1_response == "N" or "No" or "Reject") 

被解讀為

 if ([[user1_response == "N"]] or [["No"]] or [["Reject"]]) 

所以user1_response == "N"可能會返回True或False 。 No和Reject本質上都將返回True 。

你可能想要的是

 if (user1_response in {"N","No","Reject"}) 

所以我們創建了一個文字集{"N","No","Reject"} ，我們正在查看user1_response是否在該集合中。

Answer 2

代碼"No" or "Reject"被轉換為布爾值True 。 您將需要檢查輸入是否分別等於每個。

Answer 3

在這里，試試這個：

#list of strings that are classified as 'rejections'
rejections = ["no", "N", "n", "Reject"]
#starts our while loops
for i in range(100):

    user1_response = input("User One: Would you like to pick " + str(i) + "? ")
    user2_response = input("User Two: Would you like to pick " + str(i) + "? ")
    if user1_response in rejections or user2_response in rejections:
        continue

    else:

        print("")

        print("Both users picked " + str(i) + "!")

        break

Answer 4

我對此也很陌生，但希望我可以通過添加接近您的技能水平的視角來提供幫助

neg= ["n", "no", "reject"]
pos= ["y", "yes", "accept"]
##positive and negative lists to easily check for a     cass unsensitive response

for i in range(100):
    user1= input("User 1 : Would you like to pick "+      str(i)+ "?")
    user2= input("User 2 : Would you like to pick "+ str(i)+ "?")
 ## I suggest making your variable names a little shorter


##Adding .lower() allows users to enter "n' or "N" etc.
    if user1.lower() in neg or user2.lower() in neg:
    continue



    elif user1.lower() in pos and user2.lower() in pos:
            break
print"Both users guessed number "+str(i)

在我看來，這個解決方案相當容易理解，並且如果您要與他人分享您所做的事情，其他新開發人員也很容易使用。

Answer 5

條件是有問題的。

(user1_response == "N" 或 "No" 或 "Reject") 僅當 user1_response == "N" 評估為 True

但是，如果 user1 和 user2 都鍵入“Y”（user1_response ==“N”或“No”或“Reject”）計算結果為“No”並且（user2_response ==“No”或“N”或“Reject”）計算結果對“N”

組合語句 (user1_response == "N" or "No" or "Reject") or (user2_response == "No" or "N" or "Reject") 評估為 "No"

並且“No”將觸發代碼的“if”部分，因為“No”不等同於布爾值 False。 因此，不會到達代碼的“其他”部分。

這是一種可能的解決方案：

if user1_response in ("N","No","Reject") or user2_response in ("No","N","Reject"):