如何使用 gmail api 獲取我的 gmail 帳戶的每封郵件的正文？

Question

我正在嘗試使用 google oauth 和 gmail api 服務解析我的 gmail 帳戶中的每個郵件正文。 現在我只能得到消息 id 和線程 id，當我打開它們時它根本沒有意義。 所以我使用的以下代碼如下：

from __future__ import print_function
import pickle
import os.path
from googleapiclient.discovery import build
from google_auth_oauthlib.flow import InstalledAppFlow
from google.auth.transport.requests import Request

# If modifying these scopes, delete the file token.pickle.
SCOPES = ['https://www.googleapis.com/auth/gmail.readonly']

def main():
    """Shows basic usage of the Gmail API.
    Lists the user's Gmail labels.
    """
    creds = None
    # The file token.pickle stores the user's access and refresh tokens, and is
    # created automatically when the authorization flow completes for the first
    # time.
    if os.path.exists('token.pickle'):
        with open('token.pickle', 'rb') as token:
            creds = pickle.load(token)
    # If there are no (valid) credentials available, let the user log in.
    if not creds or not creds.valid:
        if creds and creds.expired and creds.refresh_token:
            creds.refresh(Request())
        else:
            flow = InstalledAppFlow.from_client_secrets_file(
                'credentials.json', SCOPES)
            creds = flow.run_local_server()
        # Save the credentials for the next run
        with open('token.pickle', 'wb') as token:
            pickle.dump(creds, token)

    service = build('gmail', 'v1', credentials=creds)

    # Call the Gmail API
    results = service.users().labels().list(userId='me').execute()
    print(service.users().messages().list(userId='me').execute())
    print(service.users().messages().get(userId='me', id='16931216e3a05048').execute())
    labels = results.get('labels', [])

    if not labels:
        print('No labels found.')
    else:
        print('Labels:')
        for label in labels:
            print(label['name'])

if __name__ == '__main__':
    main()

對於使用此行的消息 id 之一，我得到的輸出是這樣的print(service.users().messages().get(userId='me', id='16931216e3a05048').execute())

輸出是這樣的：

Answer 1

你忘了添加格式

消息.get

message = service.users().messages().get(userId=user_id, id=msg_id,
                                         format='raw').execute()

print 'Message snippet: %s' % message['snippet']

msg_str = base64.urlsafe_b64decode(message['raw'].encode('ASCII'))

mime_msg = email.message_from_string(msg_str)