[英]How can I make one guess activate multiple letters in a Hangman game?
當我使用一個包含 2 個相同字母的單詞時(例如 'snazzy'),猜測一次只能激活 1 個字母。 我怎樣才能解決這個問題?
l1=input('Input your (lowercase) letter:')
l2=input('Input your (lowercase) letter:')
l3=input('Input your (lowercase) letter:')
l4=input('Input your (lowercase) letter:')
l5=input('Input your (lowercase) letter:')
l6=input('Input your (lowercase) letter:')word=[l1,l2,l3,l4,l5,l6]
n1=''
n2=''
n3=''
n4=''
n5=''
n6=''
show=[n1,n2,n3,n4,n5,n6]
fail=0
good=0
while fail<=6 and good<6:
guess=input('Guess a letter...')
if guess in word:
print('Right!')
good=good+1
if guess==l1:
n1=guess
elif guess==l2:
n2=guess
elif guess==l3:
n3=guess
elif guess==l4:
n4=guess
elif guess==l5:
n5=guess
elif guess==l6:
n6=guess
show=[n1,n2,n3,n4,n5,n6]
else:
print('No.')
fail=fail+1
print(show)
print(word)
if fail==7:
print('Executioner wins!')
else:
print('Prisoner wins!')
澄清一下,我無法猜測這封信兩次以顯示其所有實例。
好吧,您的代碼中有很多不是最佳的,但這里有一個小的改進(這也不是最佳的)。 我使用 for 循環來查找與猜測匹配的所有字母。
num_letters = 6
word_to_guess = []
for _ in range(num_letters):
word_to_guess.append(
input('Input your (lowercase) letter:').lower().strip())
word_to_show = ['?', ] * num_letters
fail = 0
good = 0
while fail <= num_letters and good < num_letters:
guess = input('Guess a letter...').lower().strip()
if guess in word_to_guess:
print('Right!')
for i, letter in enumerate(word_to_guess):
if guess == letter:
good += 1
word_to_show[i] = letter
else:
print('No.')
fail += 1
print(word_to_show)
print('word_to_guess', word_to_guess)
print('word_to_show', word_to_show)
if fail == 7:
print('Executioner wins!')
else:
print('Prisoner wins!')
那對你有用嗎?
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.