使用html按鈕而不是Mapbox GL JS鏈接來切換GeoJSON圖層

Question

我正在制作一張涉及打開和關閉兩個GeoJSON圖層的網絡地圖。 我以前使用Mapbox JS通過刪除圖層並在單擊時使用自定義HTML按鈕添加它們來完成此操作，但是在使用Mapbox GL JS完成此操作時遇到了問題。 我要做的就是使用HTML按鈕而不是添加到創建的CSS菜單的鏈接打開和關閉兩層（顯示和隱藏）：

var layers = document.getElementById('menu');
layers.appendChild(link);

我想可以將功能綁定到button元素，但是無法使其正常工作：

document.getElementById("toggle-layer-one").onclick = function() {};

HTML：

<button data-balloon="Campsite" data-balloon-pos="right" id="toggle-layer-one"></button>

CSS

#toggle-layer-one {
background-image: url("../Assets/Campsite.svg");
background-size: 70px 70px;
height: 70px;
width: 70px;
border-top: 1px solid #fff;
}

JS

map.on('style.load', function () {
map.addSource("sample", {
    type: "geojson",
    data: "https://raw.githubusercontent.com/aarontaveras/Sample-GeoJSON-Data/master/sample.geojson"
});

map.addLayer({
    "id": "sample-point-one",
    "type": "symbol",
    "source": "sample",
    "filter": ["==", "$type", "Point"],
    "layout": {
        "icon-image": "circle-15",
        "icon-size": 1,
        "icon-anchor": "center",
    }
});

map.setFilter('sample-point-one', ['==', 'region', 'Africa']);

map.addLayer({
    "id": "sample-point-two",
    "type": "symbol",
    "source": "sample",
    "filter": ["==", "$type", "Point"],
    "layout": {
        "icon-image": "circle-15",
        "icon-size": 1,
        "icon-anchor": "center",
    }
});

map.setFilter('sample-point-two', ['==', 'region', 'Asia']);

});

// Toggle layers
var toggleableLayerIds = ["sample-point-one", "sample-point-two"];

for (var i = 0; i < toggleableLayerIds.length; i++) {
var id = toggleableLayerIds[i];

var link = document.createElement('a');
link.href = '#';
link.className = 'active';
link.textContent = id;

link.onclick = function (e) {
    var clickedLayer = this.textContent;
    e.preventDefault();
    e.stopPropagation();

    var visibility = map.getLayoutProperty(clickedLayer, 'visibility');

    if (visibility === 'visible') {
        map.setLayoutProperty(clickedLayer, 'visibility', 'none');
        this.className = '';
    } else {
        this.className = 'active';
        map.setLayoutProperty(clickedLayer, 'visibility', 'visible');
    }
};

var layers = document.getElementById('menu');
layers.appendChild(link);
}

謝謝！

Answer 1

我最終搞清楚了。

HTML：

<a id="test" href="#">TEST</a>

JS：

var toggleLayerId = ["sample-point-one"];

document.getElementById("test").onclick = function (e){
for (var index in toggleLayerId) {
    var clickedLayer = toggleLayerId[index];
    e.preventDefault();
    e.stopPropagation();

    var visibility = map.getLayoutProperty(clickedLayer, 'visibility');

    if (visibility === 'visible') {
        map.setLayoutProperty(clickedLayer, 'visibility', 'none');
        this.className = '';
    } else {
        this.className = 'active';
        map.setLayoutProperty(clickedLayer, 'visibility', 'visible');
    }
}
};