[英]Spring JPA Base Repository
我創建了一個自定義存儲庫以覆蓋持久性方法,並嘗試按照spring docs中的說明進行連接 。 我沒有收到任何錯誤,所有實體和存儲庫都在啟動時找到,並且當我調用repo.saveAll(entities)時,持久性正常工作。 但是,從未調用我的自定義代碼。 我在代碼中添加了日志語句,甚至引發了RuntimeExceptions,只是為了查看它是否正在執行,但是肯定會忽略它。 我錯過了哪一步?
@Configuration
@Profile("test")
@EnableJpaRepositories(repositoryBaseClass = SetClientInfoRepositoryImpl.class,
basePackages = {"gov.penndot.hwy.apras.common.repository" },
entityManagerFactoryRef = "serviceEntityManagerFactory",
transactionManagerRef = "serviceTransactionManager")
public class TestDatabaseConfig {
@Bean(name = "serviceDataSource")
public DataSource dataSource() {
DriverManagerDataSource dataSource = new DriverManagerDataSource();
dataSource.setDriverClassName("org.h2.Driver");
dataSource.setUrl("jdbc:h2:mem:db;DB_CLOSE_DELAY=-1");
dataSource.setUsername("sa");
dataSource.setPassword("sa");
return dataSource;
}
@Bean
public EntityManagerFactoryBuilder entityManagerFactoryBuilder() {
return new EntityManagerFactoryBuilder(new HibernateJpaVendorAdapter(), new HashMap<String, Object>(), null);
}
@Bean(name = "serviceEntityManagerFactory")
public LocalContainerEntityManagerFactoryBean serviceEntityManagerFactory(EntityManagerFactoryBuilder builder,
@Qualifier("serviceDataSource") DataSource dataSource) {
return builder
.dataSource(dataSource)
.packages("stuff")
.persistenceUnit("service")
.build();
}
@Bean(name = "serviceTransactionManager")
public PlatformTransactionManager transactionManager(
@Qualifier("serviceEntityManagerFactory") EntityManagerFactory serviceEntityManagerFactory) {
return new JpaTransactionManager(serviceEntityManagerFactory);
}
庫:
@NoRepositoryBean
public class SetClientInfoRepositoryImpl<T, ID extends Serializable> extends SimpleJpaRepository<T, ID> {
private static final Logger log = LoggerFactory.getLogger(SetClientInfoRepositoryImpl.class);
private final EntityManager em;
public SetClientInfoRepositoryImpl(JpaEntityInformation<T, ID> entityInformation, EntityManager entityManager) {
super(entityInformation, entityManager);
this.em = entityManager;
}
@Transactional
@Override
public <S extends T> S save(S entity) {
setClientInfo();
return super.save(entity);
}
@Transactional
@Override
public void deleteById(ID id) {
setClientInfo();
super.deleteById(id);
}
@Transactional
@Override
public void delete(T entity) {
setClientInfo();
super.delete(entity);
}
@Transactional
@Override
public void deleteAll(Iterable<? extends T> entities) {
setClientInfo();
super.deleteAll(entities);
}
@Transactional
@Override
public void deleteInBatch(Iterable<T> entities) {
setClientInfo();
super.deleteInBatch(entities);
}
@Transactional
@Override
public void deleteAll() {
setClientInfo();
super.deleteAll();
}
@Transactional
@Override
public void deleteAllInBatch() {
setClientInfo();
super.deleteAllInBatch();
}
@Transactional
@Override
public <S extends T> S saveAndFlush(S entity) {
setClientInfo();
return super.saveAndFlush(entity);
}
@Transactional
@Override
public <S extends T> List<S> saveAll(Iterable<S> entities) {
setClientInfo();
super.saveAll(entities);
throw new RuntimeException("foo");
}
private void setClientInfo() {
log.debug("Entering setClientInfo method");
[stuff]
}
}
好的,這是一個絕望的主意,但值得一試...
創建一個定制的存儲庫界面:
public interface SetClientInfoRepository<T, ID> extends JpaRepository<T, ID> {
}
通過您的定制基礎存儲庫實現此存儲庫接口:
public class SetClientInfoRepositoryImpl<T, ID extends Serializable> extends SimpleJpaRepository<T, ID> implements SetClientInfoRepository<T, ID> {
}
...最后通過您的存儲庫接口而不是JpaRepository
擴展此接口
通過這種方式,Spring 必須從您的實現中創建存儲庫代理,因為它無法使用其他任何類。 另外,如果由於某種原因它不能創建存儲庫,則在啟動過程中會得到更多信息。
使用定制存儲庫接口本身並不是一件壞事,因為您總是有很大的機會希望以后向存儲庫中添加一些通用的定制方法,這樣會很方便。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.