[英]Write a program that accepts a positive integer from the user and prints the first four multiples of that integer. Use a while loop
[英]Program that reads 2 positive integer and print the first multiples of it only using “while”
我正在嘗試編寫一個程序,該程序讀取2個正整數(m和n),然后僅使用while循環打印m的n個第一個正整數。
這是原始問題
用Python 3.x語言編寫一個程序,該程序讀取兩個正整數m和n,並打印前n個正整數,該正整數是m的倍數。
代碼的輸出應如下所示:
Type a positive integer for m: 9
Type a positive integer for n: 5
The first 5 positive integers multiples of 9 are:
9
18
27
36
45
到目前為止,我已經完成了:
m = int(input("Type a integer for m: "))
n = int(input("Type a integer for n: "))
i = 1
print()
print("The first ",n,"positive integers multiples of ", m," are:")
while i <= n:
m = m * i
print(m)
i = i + 1
我想了解如何解決此問題,並且我意識到使用for或如果這樣做會更容易
你的問題在這一行
m = m * i
您正在緩存一個中間值,然后在下一次迭代中將其乘以,因此,第一次您將m
乘以,但在下一次迭代中,您將乘以先前的中間值而不是原始的m
您可以這樣更改循環:
while i <= n:
print(m * i) # you don't need to save the intermediate result, you can just print it
i = i + 1
Nullman的解決方案是正確的選擇,無論如何,這里的代碼已更正,以防萬一它可以幫助您更好地理解錯誤:
m = 9
n = 5
i = 1
print()
print("The first ",n,"positive integers multiples of ", m," are:")
while i <= n:
multiple = m * i
print(multiple)
i = i + 1
您不能使用if
,但實際上可以for
:
m = 9
n = 5
i = 1
print()
print("The first ",n,"positive integers multiples of ", m," are:")
for i in range(1, n + 1):
multiple = m * i
print(multiple)
i = i + 1
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