無法在 Xpath 中找到值（元素）

Question

即使網頁中存在該元素，也無法在 xpath 中找到該元素。實際上，代碼既不會拋出異常，也不會找到元素。

for c in range(sheet.ncols):
    for r in range(sheet.nrows):
        st = (sheet.cell_value(r, c))
        print(str(st))
        xpath1 = "//input[@value='Analyze' and contains(@onclick,'" + str(st) + "')]"
        #xpath = "//input[@value='Analyze'][.='" + st + "']"
        print(driver.title)
        print(len(driver.find_elements_by_xpath(xpath1)))
        if driver.find_elements_by_xpath(xpath1):
            print("loop")
            driver.find_element_by_xpath(xpath1).click()  # Here new window will open
            time.sleep(2)
            #Main_Window = driver.current_window_handle
            driver.switch_to.window(driver.window_handles[-1])
            driver.find_element_by_xpath('/html/body/table/tbody/tr[4]/td/table/tbody/tr[9]/td[3]/input').click()
            driver.close()
            driver.switch_to.window(driver.window_handles[-1])
            xpath2 = "//*[@id='create_button']"
            xpath3 = "//*[@id='update_button']"
            if check_exists_by_xpath(xpath2):
                driver.find_element_by_xpath(xpath2).click()
                driver.close()
                driver.switch_to.window(driver.window_handles[0])

            elif check_exists_by_xpath(xpath3):
                driver.close()
                driver.switch_to.window(driver.window_handles[0])
                continue

預期輸出應該是：

23 ST 1 回路 45 ST 1 6 ST 1 89 ST 1

但是在運行上面的代碼時得到了下面的輸出：23 ST 1 loop 4 ST 0 56 ST 0 7 ST 0

代碼有什么問題？

提前致謝。

Answer 1

只需要切換到正確的窗口和框架。

      if check_exists_by_xpath(xpath2):
            driver.find_element_by_xpath(xpath2).click()

      #else not required as you are not using the xpath3 to click

      driver.close()
      driver.switch_to.window(driver.window_handles[0])
      driver.switch_to.frame(base_frame_locator/index)
      driver.switch_to.frame(child_frame_locator/index)
      continue

Answer 2

我也想查看您的 HTML 或獲取網頁鏈接以檢查 xpath。 但是，根據您的輸出，我認為您很可能沒有切換到 [0] 索引窗口。 您正在 if 語句中執行窗口切換，因此如果這兩個條件都不滿足，您將不會切換窗口。 嘗試將窗口開關從 if 中取出，可能是這樣的：

for c in range(sheet.ncols):
    for r in range(sheet.nrows):
        st = (sheet.cell_value(r, c))
        print(str(st))
        xpath1 = "//input[@value='Analyze' and contains(@onclick,'" + str(st) + "')]"
        #xpath = "//input[@value='Analyze'][.='" + st + "']"
        print(driver.title)
        print(len(driver.find_elements_by_xpath(xpath1)))
        if driver.find_elements_by_xpath(xpath1):
            print("loop")
            driver.find_element_by_xpath(xpath1).click()  # Here new window will open
            time.sleep(2)
            #Main_Window = driver.current_window_handle
            driver.switch_to.window(driver.window_handles[-1])
            driver.find_element_by_xpath('/html/body/table/tbody/tr[4]/td/table/tbody/tr[9]/td[3]/input').click()
            driver.close()
            driver.switch_to.window(driver.window_handles[-1])
            xpath2 = "//*[@id='create_button']"
            xpath3 = "//*[@id='update_button']"
            if check_exists_by_xpath(xpath2):
                driver.find_element_by_xpath(xpath2).click()
            driver.close()
            driver.switch_to.window(driver.window_handles[0])

我認為您甚至不需要第二個 if 語句，因為它只包含

driver.close()
driver.switch_to.window(driver.window_handles[0])