Array.every函數未在Object的所有元素上運行

Question

我正在嘗試使用以下代碼在temp1內部搜索是否有任何值具有字符串"processado"

let temp1 = [{
    "id":7089,
    "value":"R$ 50,00",
    "name":"Daiany Nascimento",
    "date":"18/03/2019",
    "type":"Cobrança",
    "status":{
        "status":"Paga",
        "icon":"paid"
    },
    "credit_release_date":"Não Processado",
    "credit_release_description":"— — — —"
}]

let b = []

temp1.forEach((a,index_a) => { 
Object.values(a).every((value,index,array) => {
    let expression = new RegExp("processado", "i") //expression to search
    if (typeof value == "object") {
      Object.values(value).every(valueOfObject => {    
        if (expression.test(valueOfObject)) {
          b.push(temp1[index_a])
          return false;
        } else {
          return true
        }
      })
    }
    else if (expression.test(value)){ 
      b.push(temp1[index_a])
      return false
    }
      else {
      return true
    }
  })
})

但是， 數組b保持為空。 如果我嘗試搜索字符串"Cobrança" ，則數組b將被填充，因為它應該這樣做。 我認為，如果我嘗試搜索狀態 鍵 之后存儲在鍵上的值 ，則會出問題。

Answer 1

您需要在if (typeof value == "object")內部return Object.values(value).every(valueOfObject....

 let temp1 = [{"id":7089,"value":"R$ 50,00","name":"Daiany Nascimento","date":"18/03/2019","type":"Cobrança","status":{"status":"Paga","icon":"paid"},"credit_release_date":"Não Processado","credit_release_description":"— — — —"}] let b = [] temp1.forEach((a,index_a) => { Object.values(a).every((value,index,array) => { let expression = new RegExp("processado", "i") //expression to search if (typeof value == "object") { return Object.values(value).every(valueOfObject => { if (expression.test(valueOfObject)) { b.push(temp1[index_a]) return false; } else { return true } }) } else if (expression.test(value)){ b.push(temp1[index_a]) return false } else { return true } }) }) console.log(b) 

一種更簡單，更簡潔的方法是使用遞歸， filter()和some() 。 在這里，對我來說， every()沒有任何意義

 let temp1 = [{"id":7089,"value":"R$ 50,00","name":"Daiany Nascimento","date":"18/03/2019","type":"Cobrança","status":{"status":"Paga","icon":"paid"},"credit_release_date":"Não Processado","credit_release_description":"— — — —"}] function check(obj,regex){ return Object.values(obj).some(x =>{ let y; if(typeof x === "object") y = check(x,regex); return y || regex.test(x); }); } let b = temp1.filter(x => check(x,/Processado/i)) console.log(b) 

Answer 2

為什么不考慮使用遞歸檢查對象是否有任何值？ 我認為這可以縮短代碼，並且更加直接。

此外， 我 Array.prototype.some更有意義在這種情況下比Array.prototype.every （除非我失去了一些東西）：

 const temp1 = [{ "id": 7089, "value": "R$ 50,00", "name": "Daiany Nascimento", "date": "18/03/2019", "type": "Cobrança", "status": { "status":"Paga", "icon":"paid" }, "credit_release_date": "Não Processado", "credit_release_description": "— — — —" }]; const b = []; const expression = new RegExp('processado', 'i'); const hasExpr = obj => Object.values(obj).some((value, i) => { if (typeof value === 'object') return hasExpr(value); return expression.test(value); }); temp1.forEach(item => { if (hasExpr(item)) b.push(item); }); console.log(b);