[英]How to use hive variable substitution rightly
在蜂巢中使用變量替換時,遇到一些錯誤,但需要您的幫助。
我的代碼:
set hievar:b='on t1.id=t2.id where t2.id is null';
select * from t_old as t1 full outer join t_new as t2 ${b};
當我在hive shell中運行此代碼時,它給了我一些關於${b}
錯誤。
我也嘗試這樣:
set hivevar:c='select * from t_old as t1 full outer join t_new as t2 on t1.id=t2.id where t2.id is null';
${c};
它給了我同樣的錯誤。
修復hivevar
命名空間名稱(在您的代碼中為hievar
)並刪除引號,因為引號也會在Hive中傳遞。
例:
set hivevar:b=where 1=1; --without quotes
select 1 ${hivevar:b}; --you can do without hivevar: as in your example
結果:
OK
1
Time taken: 0.129 seconds, Fetched: 1 row(s)
第二個例子:
hive> set hivevar:c=select 1 where 1=1;
hive> ${c};
OK
1
Time taken: 0.491 seconds, Fetched: 1 row(s)
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