Snowflake中具有多個JSON對象的橫向扁平數組

Question

我有一個包含多個JSON對象的數組。 位於表中的任何JSON數組中的最大元素數為8。

這是數組原始值的示例：

                              variants
----------------------------------------------------------------

[
      {
        "id": 12388362846279,
        "inventory_quantity": 10,
        "sku": “sku1”
      },
      {
        "id": 12388391387207,
        "inventory_quantity": 31,
        "sku": “sku2”
      },
      {
        "id": 12394420142151,
        "inventory_quantity": 12,
        "sku": “sku3”
      },
      {
        "id": 12394426007623,
        "inventory_quantity": 4,
        "sku": “sku4”
      },
      {
        "id": 12394429022279,
        "inventory_quantity": 9,
        "sku": “sku5”
      },
      {
        "id": 12394431414343,
        "inventory_quantity": 15,
        "sku": “sku6”
      },
      {
        "id": 12394455597127,
        "inventory_quantity": 22,
        "sku": “sku7”
      },
      {
        "id": 12394459856967,
        "inventory_quantity": 0,
        "sku": “sku8”
      }
    ]

我的查詢嘗試展平並解析數組以為每個對象返回一行：

select 
      variants[0]:sku,
      variants[0]:inventory_quantity,
      variants[1]:sku,
      variants[1]:inventory_quantity,
      variants[2]:sku,
      variants[2]:inventory_quantity,
      variants[3]:sku,
      variants[3]:inventory_quantity,
      variants[4]:sku,
      variants[4]:inventory_quantity,
      variants[5]:sku,
      variants[5]:inventory_quantity,
      variants[6]:sku,
      variants[6]:inventory_quantity,
      variants[7]:sku,
      variants[7]:inventory_quantity
from table
, lateral flatten(input => variants)

但是，我的輸出返回重復/重復的值：

+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+

我希望我的輸出看起來類似於以下內容：

+------+----+
| sku1 | 10 |
+------+----+
| sku2 | 31 |
+------+----+
| sku3 | 12 |
+------+----+
| sku4 | 4  |
+------+----+
| sku5 | 9  |
+------+----+
| sku6 | 15 |
+------+----+
| sku7 | 22 |
+------+----+
| sku8 | 0  |
+------+----+

Answer 1

使用LATERAL FLATTEN不需要顯式引用數組位置。 數組的每個成員成為其自己的行。 因此，要獲得上面想要的結果，只需使用：

select v.value:sku::varchar, 
       v.value:inventory_quantity 
from table, 
lateral flatten(input => table.variants) v
;

如果表中的某些列在每行中要引用的數組之外，只需將它們包括在SELECT中。 本質上，將數組中平展的行隱式“連接”到表的非嵌套列...