Scala：如何在函數中返回元組？ “類型不匹配”

Question

我正在使用庫gremlin-scala與 Janusgraph 進行交互。

使用 DSL，插入新頂點的一種方法是執行以下操作：

val Id = Key[Long]("id")
val Name = Key[String]("name")
graph + ("label", Id -> 42, Name -> "Mike")

我想把這部分變成一個函數("label", Id -> 42, Name -> "Mike")

case class VertexModel(id: Long, name: String) {
  def toVertex: (Label, KeyValue[Long], KeyValue[String]) = {
    val Id = Key[Long]("id")
    val Name = Key[String]("name")
    ("item", Id -> id, Name -> name)
  }
}

val model = VertexModel(1, "Bill")
graph + model.toVertex

這失敗並出現以下錯誤：

Error:(26, 11) type mismatch;
 found   : T1
 required: gremlin.scala.Label
    (which expands to)  String
    graph + vertex
Error:(26, 11) type mismatch;
 found   : T2
 required: gremlin.scala.KeyValue[Long]
    graph + vertex
Error:(26, 11) type mismatch;
 found   : T3
 required: gremlin.scala.KeyValue[String]
    graph + vertex

不知道如何解決這個問題。

Answer 1

為什么需要擴展方法toVertex ？

這不就像

import gremlin.scala._
import org.apache.tinkerpop.gremlin.tinkergraph.structure.TinkerGraph

object App {

  implicit val graph: ScalaGraph = TinkerGraph.open.asScala

  case class VertexModel(id: Long, name: String) 

  val model = VertexModel(1, "Bill")
  graph + model
}

?

生成.sbt

scalaVersion := "2.12.8"
libraryDependencies += "com.michaelpollmeier" %% "gremlin-scala" % "3.4.0.4"
libraryDependencies += "org.apache.tinkerpop" % "tinkergraph-gremlin" % "3.4.0"