[英]How to wait for multiple futures to complete in Vapor Swift?
我試圖弄清楚如何等待多個期貨完成。 我知道如何使用以下方法異步等待它們: summaryFuture.whenSuccess {}
但這僅處理一種情況。 我需要等待summaryFuture和SponsorFuture都完成,然后再使用這兩者,然后再發送回響應。
let summaryFuture = client.post(summaryURL) { post in
post.http.headers.add(name: "authtoken", value: token)
}.flatMap(to: SummaryModel.self) { (response) in
return try response.content.decode(SummaryModel.self)
}
let sponsorEnrollerFuture = client.post(sponsporEnroller) { post in
post.http.headers.add(name: "authtoken", value: token)
}.flatMap(to: SponsorEnrollerModel.self) { (response) in
return try response.content.decode(SponsorEnrollerModel.self)
}
您可以使用.and
或.flatten
對於.flatten
您的期貨應返回Void
,因此最終結果也將為Future<Void>
。
.and
可以這樣使用
let summaryFuture = client.post(summaryURL) { post in
post.http.headers.add(name: "authtoken", value: token)
}.flatMap(to: SummaryModel.self) { (response) in
return try response.content.decode(SummaryModel.self)
}
let sponsorEnrollerFuture = client.post(sponsporEnroller) { post in
post.http.headers.add(name: "authtoken", value: token)
}.flatMap(to: SponsorEnrollerModel.self) { (response) in
return try response.content.decode(SponsorEnrollerModel.self)
}
// Now combine the two futures
return summaryFuture.and(sponsorEnrollerFuture).map { summary, sponsorEnrolled in
print("summary: \(summary)")
print("sponsorEnrolled: \(sponsorEnrolled)")
}
好的。 我想到了。
要等待多個Future完成,您必須使用.add
。 在我的情況下。
let summaryFuture = client.post(summaryURL) { post in
post.http.headers.add(name: "authtoken", value: token)
}.flatMap(to: SummaryModel.self) { (response) in
return try response.content.decode(SummaryModel.self)
}
let sponsorEnrollerFuture = client.post(sponsporEnroller) { post in
post.http.headers.add(name: "authtoken", value: token)
}.flatMap(to: SponsorEnrollerModel.self) { (response) in
return try response.content.decode(SponsorEnrollerModel.self)
}
// Now combine the two futures
let multipleFutures = summaryFuture.add(sponsorEnrollerFuture)
// Now I can use
mutipleFutures.whenSuccess = {(summary, sponsorEnroller) in ...}
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