[英]UID for same user is different in Firebase database and authentication
[英]Is there a way to delete anonymous user from Firebase Database Authentication and Firebase Database UID?
當前發生的情況:當用戶使用onBackPressed
和case R.id.logoutMenuOption
作為匿名用戶注銷時,他們的 Firebase Auth 和 Firebase 數據庫 Uid 被正確刪除。 除了,當用戶滑動關閉應用程序時,將調用onDestroy()
方法,但他們的 Firebase Auth 和 Firebase 數據庫 Uid 仍然保留在數據庫中。 當用戶滑動關閉應用程序時,我使用onDestroy()
。
我需要做什么:當用戶滑動關閉應用程序時,將調用onDestroy()
和removeAnonymousVendorUser()
方法以從實時數據庫中刪除匿名用戶身份驗證及其用戶 Uid。
到目前為止我做了什么:我創建了removeAnonymousVendorUser()
方法並將它放在onDestroy()
方法中。 我還將展示它是如何在我的其他注銷方法中使用的,在那些方法中它確實有效,但它不適用於onDestroy()
@Override
protected void onDestroy() {
super.onDestroy();
//TODO: Figure out how to delete UID and user when they sign out
removeAnonymousVendorUser();
FirebaseAuth.getInstance().signOut();
finish();
}
刪除匿名用戶 Firebase Auth 數據和 Firebase 數據庫數據的方法:
private void removeAnonymousVendorUser() {
if (FirebaseAuth.getInstance().getCurrentUser() != null) {
FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
user.delete();
}
DatabaseReference vendorIdReference = FirebaseDatabase.getInstance().getReference("Vendor");
vendorIdReference.removeValue();
}
用戶單擊注銷菜單選項按鈕時的注銷方法:
//Logout Menu Option Button
@Override
public boolean onOptionsItemSelected(MenuItem item) {
switch (item.getItemId()) {
// If Logout Button is clicked within 2 Seconds log user out
case R.id.logoutMenuOption:
if (logoutAppPressAgain + 2000 > System.currentTimeMillis()) {
logoutToast.cancel();
removeAnonymousVendorUser();
FirebaseAuth.getInstance().signOut();
removeAnonymousVendorUser();
Intent logoutIntent = new Intent(VendorMapsActivity.this, WelcomeActivity.class);
startActivity(logoutIntent);
finish();
} else {
logoutToast = Toast.makeText(getBaseContext(), R.string.press_button_again_to_logout, Toast.LENGTH_SHORT);
logoutToast.show();
}
logoutAppPressAgain = System.currentTimeMillis();
}
return super.onOptionsItemSelected(item);
}
用戶按兩次后退時的注銷方法:
public void onBackPressed() {
if (exitAppPressBack + 2000 > System.currentTimeMillis()) {
exitAppBackToast.cancel();
super.onBackPressed();
removeAnonymousVendorUser();
FirebaseAuth.getInstance().signOut();
Intent logoutIntent = new Intent(VendorMapsActivity.this,
WelcomeActivity.class);
startActivity(logoutIntent);
finish();
} else {
exitAppBackToast = Toast.makeText(getBaseContext(),
R.string.press_back_one_more_time_to_exit, Toast.LENGTH_SHORT);
exitAppBackToast.show();
}
exitAppPressBack = System.currentTimeMillis();
}
這是在匿名登錄時創建用戶的代碼:
public void sellAnonymously(View view) {
circProgressBar.setVisibility(View.VISIBLE);
firebaseAuth.signInAnonymously().addOnSuccessListener(VendorLoginActivity.this, new OnSuccessListener<AuthResult>() {
@Override
public void onSuccess(AuthResult authResult) {
Toast.makeText(VendorLoginActivity.this, "Success! Enjoy the app!", Toast.LENGTH_LONG).show();
String client_id = firebaseAuth.getCurrentUser().getUid();
DatabaseReference client_db = FirebaseDatabase.getInstance().getReference().child("Vendor").child(client_id);
client_db.setValue(true);
circProgressBar.setVisibility(View.INVISIBLE);
// Sends anonymous user to VendorMapsActivity
startActivity(new Intent(VendorLoginActivity.this, VendorMapsActivity.class));
}
});
}
要刪除用戶,請在Firebase文檔中顯示有關刪除用戶的信息,調用user.delete()
:
FirebaseUser user = FirebaseAuth.getInstance().getCurrentUser();
user.delete()
要從當前用戶的數據庫中刪除數據,請在對該數據的引用上調用removeValue()
,如有關刪除數據的Firebase文檔中所示:
ref.removeValue()
您可以將Cloud Functions for Firebase結合使用。 在這種情況下,您通過從數據庫中刪除其數據來響應被刪除的用戶。 有關此內容的簡短說明,請參閱有關刪除用戶時觸發Cloud Functions的Firebase文檔:
exports.deleteUserData = functions.auth.user().onDelete((user) => {
// ...
})
User user = FirebaseAuth.instance.currentUser;
await user.delete();
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