[英]How can I get on the PHP side the values of my array, and insert them into my database?
我已將帶有 jquery ajax 的數組發送到我的文件 addServicesRequest.php 中,但我不知道如何在我的 sql 插入請求中一一使用數組的值...
如果有人可以提供幫助,那就太好了! 非常感謝!
這是我的 jquery 代碼:(效果很好)
$('#addServices').click(function(){
$.ajax({
type: "POST",
data: {chosenServices!chosenServices},
url: "addServicesRequest.php"
});
});
這是我的 php : (addServicesRequest.php)
session_start();
require_once __DIR__ . ('/connectDatabase.php');
/*foreach ($postTest as $service){
var_dump($_POST["service"]);
}*/
$insertServices = $bdd->prepare('INSERT INTO CHOSEN_SERVICES
(id_user, id_service, status)
VALUES (?, ?, ?)');
$insertServices->execute(array(
"id_user" => $_SESSION['id'],
"id_service" => $_POST['service'],
"status" => "payed"
));
嗨,你可以這樣做:
你的 php 腳本:
if (isset($_POST["action"])) {
$action = $_POST["action"];
switch ($action) {
case 'INS':
if (isset($_POST["data"])) {
$data = $_POST["data"];
$insertServices = $bdd->prepare('INSERT INTO CHOSEN_SERVICES
(id_user, id_service, status)
VALUES (?, ?, ?)');
$insertServices->execute(array(
"id_user" => $_SESSION['id'],
"id_service" => $data['service'],
"status" => "payed"
));
$response = array("status"=> "success","message"=>"everything its okay");
echo json_encode($response);
}
break;
}//end switch
}//endif
其中 action 是要執行 SLC、UPD、DEL 等的命令,id 是參數
然后在你的 ajax 中:
var service = $("#yourelement").val();
function insertServicePayment(service) {
var data= {
service : service
};
return $.ajax({
type: "POST",
url: "addServicesRequest.php",
data: {data:data}
})
}
像這樣稱呼它:
insertServicePayment(service).done(function(response){
var data=JSON.parse(response);
if (data != null) {
//fill your forms using your data or display a message
}
})
希望能幫助到你
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