在某個子字符串之后獲取字符串

Question

如何在某個子字符串之后獲取字符串：

strings = ["Mayo", "Nice May", "nice May comes", "nice Mayo", "nice Mayo comes"]
substring = "May"

我只想獲取其中包含單詞“ May”的字符串， 而不僅僅是包含序列“ May” 。

我已經嘗試過以下代碼：

for x in strings:
    if "May" in x:
        print(x)

for x in strings:
    if x.find("May"):
        print(x)

我想要：

Nice May                                                                                                                       

nice May comes

我得到：

Mayo                                                                                                                               
Nice May                                                                                                                           
nice May comes                                                                                                                     
nice Mayo                                                                                                                          
nice Mayo comes                                                                                                                    
abcMayabc

Answer 1

使用split() ，檢查substring是否in用空格分隔的strings的elem中：

strings = ["Mayo", "Nice May", "nice May comes", "nice Mayo", "nice Mayo comes"]
substring = "May"

for x in strings:
    if substring in x.split(" "): print(x)

輸出 ：

Nice May
nice May comes

使用list comprehension ：

print([x for x in strings if substring in x.split()])

輸出 ：

['Nice May', 'nice May comes']

Answer 2

使用正則表達式邊界。

例如：

import re

strings = ["Mayo", "Nice May", "nice May comes", "nice Mayo", "nice Mayo comes"]
substring = "May"

for i in strings:
    if re.search(r"\b{}\b".format(substring), i):
        print(i)

輸出：

Nice May
nice May comes