隨機通道中的后台任務Discord.py

Question

我正在嘗試讓我的后台任務使用random.choice()在不同的通道中發送。 當我打開漫游器時，它將僅在一個隨機通道中發送，並且僅在該通道中發送。 有沒有一種方法可以在每次循環時發送不同的通道？

async def test_loop():
    await client.wait_until_ready()
    channels = ['550528972226', '5149003563352', '514900351233', '5799132312340']
    channel = client.get_channel(random.choice(channels))
    while not client.is_closed:
        time = random.randint(1,5)+random.random()
        monies = random.randint(100,250)
        emojigrab = '💵'
        emojimsg = await client.send_message(channel, emojigrab)
        await client.add_reaction(emojimsg, "💰")
        pay = await client.wait_for_reaction(emoji="💰", message=emojimsg, timeout=1800,
                                             check=lambda reaction, user: user != client.user)
        if pay:
            await client.delete_message(emojimsg)
            await client.send_message(channel, "{} secures the bag for ${:,}".format(pay.user.mention, monies))
            add_dollars(pay.user, monies)
            await asyncio.sleep(int(time))

Answer 1

當前， channel = client.get_channel(random.choice(channels))在您的while循環之外，這意味着可變channel永遠不會改變。 每次發送新消息時，將其移至while循環內即可進行更改。

async def test_loop():
    await client.wait_until_ready()
    channels = ['550528972226', '5149003563352', '514900351233', '5799132312340']
    while not client.is_closed:
        channel = client.get_channel(random.choice(channels))
        time = random.randint(1,5)+random.random()
        monies = random.randint(100,250)
        emojigrab = '💵'
        emojimsg = await client.send_message(channel, emojigrab)
        await client.add_reaction(emojimsg, "💰")
        pay = await client.wait_for_reaction(emoji="💰", message=emojimsg, timeout=1800,
                                             check=lambda reaction, user: user != client.user)
        if pay:
            await client.delete_message(emojimsg)
            await client.send_message(channel, "{} secures the bag for ${:,}".format(pay.user.mention, monies))
            add_dollars(pay.user, monies)
            await asyncio.sleep(int(time))