一個襯里-嵌套循環

Question

試圖避免嵌套的for循環，但是我不確定如何在一個襯里使用words = x.split()和words[y:y+n] 。

n = 1
for x in data:
    words = x.split()
    for y in range(len(words)-n+1):
        print(words[y:y+n])

到目前為止，我正在處理以下內容：

data = ' '.join([(x, y) for x in data words = x.split() for y in range(len(words)-n+1) words[y:y+n]])

Answer 1

分配臨時變量的一種解決方法是改為遍歷1個元組：

data = ' '.join(words[y:y+n] for x in data for words in (x.split(),) for y in range(len(words)-n+1))

Answer 2

n = 1
for x in data:
    words = x.split()
    for y in range(len(words)-n+1):
        print(words[y:y+n])

n永遠不會改變，所以總是1

for x in data:
    words = x.split()
    for y in range(len(words)-1+1):
        print(words[y:y+1])

所以簡化

for x in data:
    words = x.split()
    for y in range(len(words)):
        print(words[y])

這基本上是

for x in data:
    for word in x.split():
        print(word)

讓我們去

data=' '.join(word for x in data for word in x.split())