[英]Extend ImmutableList.of() by another List
我想簡化與ImmutableList.of()功能相關的現有代碼
我想通過消除“new ...”構造函數來嘗試優化第二個List的創建,但當然我無法通過調用.add()來擴展不可變列表。
當前代碼:
static final ImmutableList<ProductCodeEnum> PRODUCTS = ImmutableList.of(ProductCodeEnum.A, ProductCodeEnum.B, ProductCodeEnum.C);
static final ImmutableList<ProductCodeEnum> PRODUCTS_EXTENDED_LIST = new ImmutableList.Builder<ProductCodeEnum>().addAll(PRODUCTS)
.add(ProductCodeEnum.D)
.add(ProductCodeEnum.E)
.build();
預期代碼如:
static final ImmutableList<ProductCodeEnum> PRODUCTS = ImmutableList.of(ProductCodeEnum.A, ProductCodeEnum.B, ProductCodeEnum.C);
static final ImmutableList<ProductCodeEnum> PRODUCTS_EXTENDED = PRODUCTS + ImmutableList.of(ProductCodeEnum.D, ProductCodeEnum.E);
我想你用的是Guava ImmutableList?
在這種情況下,您的代碼將如下所示:
static final ImmutableList<ProductCodeEnum> PRODUCTS = ImmutableList.of(ProductCodeEnum.A, ProductCodeEnum.B, ProductCodeEnum.C);
static final ImmutableList<ProductCodeEnum> PRODUCTS_EXTENDED = ImmutableList.builder().addAll(PRODUCTS).add(ProductCodeEnum.D, ProductCodeEnum.E).build();
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