[英]Sequelize.js,How to insert a model with one to many to many relationship
我正在使用 sequlize.js 創建一個一對多的模型,它可以工作,但我想創建一個一對多對多的模型,我不知道從哪里開始
現在我已經定義了三個模型,下面是它們的關系
Projects.associate = () => {
Projects.Colors = Projects.hasMany(ProjectColors, { foreignKey: 'project_id', sourceKey: 'id' });
};
ProjectColors.associate = () => {
Projects.Sizes = ProjectColors.hasMany(ProjectSizes, { foreignKey: 'project_color_id', sourceKey: 'id' });
};
有一個對象,我想通過項目模型創建
const project = {
name: 'xxproject',
colors:[
{
color: 'red',
sizes:[
{size: 'L'}
]
},
{
color: 'bule',
sizes:[
{size: 'L'},
{size: 'M'}
]
},
]
}
我嘗試了像 Office Document 這樣的一對多,它可以很好地工作如下
await Projects.create(project, {
include: [ Projects.Colors ],
});
如果我更改代碼,它會出錯
await Projects.create(project, {
include: [{
model: Projects.Colors,
}],
});
這是錯誤堆棧
2019-04-04 10:57:10,074 ERROR 60510 [-/127.0.0.1/-/20ms POST /api/v1/projects] nodejs.TypeError: self._expandAttributes is not a function
at Function._conformOptions (/Users/jaytam/school/garment-production-backend/node_modules/sequelize/lib/model.js:198:12)
at Function._conformInclude (/Users/jaytam/school/garment-production-backend/node_modules/sequelize/lib/model.js:264:12)
at options.include.options.include.map.include (/Users/jaytam/school/garment-production-backend/node_modules/sequelize/lib/model.js:213:59)
at Array.map (<anonymous>)
at Function._conformOptions (/Users/jaytam/school/garment-production-backend/node_modules/sequelize/lib/model.js:213:39)
at new Model (/Users/jaytam/school/garment-production-backend/node_modules/sequelize/lib/model.js:3070:24)
at new projects (/Users/jaytam/school/garment-production-backend/node_modules/sequelize/lib/sequelize.js:340:19)
at Function.build (/Users/jaytam/school/garment-production-backend/node_modules/sequelize/lib/model.js:1966:12)
at Function.create (/Users/jaytam/school/garment-production-backend/node_modules/sequelize/lib/model.js:2017:17)
at ProjectController.create (/Users/jaytam/school/garment-production-backend/app/controller/projects.js:42:20)
at Object.callFn (/Users/jaytam/school/garment-production-backend/node_modules/egg-core/lib/utils/index.js:44:21)
at Object.classControllerMiddleware (/Users/jaytam/school/garment-production-backend/node_modules/egg-core/lib/loader/mixin/controller.js:87:20)
at Object.callFn (/Users/jaytam/school/garment-production-backend/node_modules/@eggjs/router/lib/utils.js:12:21)
at wrappedController (/Users/jaytam/school/garment-production-backend/node_modules/@eggjs/router/lib/egg_router.js:322:18)
at dispatch (/Users/jaytam/school/garment-production-backend/node_modules/@eggjs/router/node_modules/koa-compose/index.js:44:32)
at next (/Users/jaytam/school/garment-production-backend/node_modules/@eggjs/router/node_modules/koa-compose/index.js:45:18)
at /Users/jaytam/school/garment-production-backend/node_modules/@eggjs/router/lib/router.js:190:18
at dispatch (/Users/jaytam/school/garment-production-backend/node_modules/@eggjs/router/node_modules/koa-compose/index.js:44:32)
at /Users/jaytam/school/garment-production-backend/node_modules/@eggjs/router/node_modules/koa-compose/index.js:36:12
at dispatch (/Users/jaytam/school/garment-production-backend/node_modules/@eggjs/router/lib/router.js:195:33)
at dispatch (/Users/jaytam/school/garment-production-backend/node_modules/koa-compose/index.js:42:32)
at /Users/jaytam/school/garment-production-backend/app/middleware/handleGetInt.js:22:11
事實上,我想這樣編碼,但上面的代碼不起作用
await Projects.create(project, {
include: [{
model: Projects.Colors,
include: [{
model: Projects.Sizes,
}],
}],
});
我模仿 Sequlize.js 文檔,改變他們的關系定義
Projects.Colors = app.model.ProjectColors.belongsTo(Projects, { foreignKey: 'project_id', targetKey: 'id' });
app.model.ProjectColors.Sizes = app.model.ProjectColors.hasMany(app.model.ProjectSizes, { foreignKey: 'project_color_id', sourceKey: 'id' });
創建代碼
await Projects.create(project, {
association: Projects.Colors,
include: [ ProjectColors.Sizes ],
});
或者
await Projects.create(project, {
include: [{
association: Projects.Colors,
include: [{
association: ProjectColors.Sizes,
}],
}],
})
兩種方式只創建項目,每種方式都沒有創建顏色和大小
[2019-04-04 14:22:15.564] [cfork:master:60831] worker:60969 exit (code: 0, exitedAfterDisconnect: true, state: dead, isDead: true, isExpected: true, worker.disableRefork: false)
{ name: 'sadqw',
cycle: 230,
fund: 1230123,
manage_by: 'dsa',
project_colors: [ { color: 'asd', imageUrl: '', project_sizes: [Array] } ],
status: '0' }
2019-04-04 14:26:24,276 INFO 60980 [egg-sequelize](1ms) Executed (default): INSERT INTO `projects` (`id`,`name`,`cycle`,`fund`,`manage_by`,`created_at`,`updated_at`,`status`) VALUES (DEFAULT,'sadqw',230,1230123,'dsa','2019-04-04 06:26:24','2019-04-04 06:26:24','0');
根據續集文檔的這一部分,您應該能夠按如下方式嵌套(取決於您使用的sequelize
版本):
return Projects.create(project, {
include: [{
association: Projects.Colors,
include: [ Colors.Sizes ]
}]
});
乍一看,你有Projects.Colors
和Projects.Sizes
,但我認為它應該是Colors.Sizes
因為那是多對多的關系。
希望有幫助!
首先,嘗試將 projectColors 關聯更改為此(假設您收到models
作為參數):
ProjectColors.associate = () => {
ProjectColors.Sizes = ProjectColors.hasMany(models.project_size, { foreignKey: 'project_color_id', sourceKey: 'id' });
ProjectColors.Projects = ProjectColors.belongsTo(models.project)
};
其次,嘗試添加到 ProjectSizes:
ProjectSizes.associate = () => {
ProjectSizes.Colors = ProjectSizes.belongsTo(models.project_color, { foreignKey: 'project_color_id'});
};
注意:模型名稱(您在models.
之后使用)是模型定義中定義的名稱( Sequelize.define([modelname]
)。
如果有幫助,請告訴我。
我相信創建應該是這樣的:
await Projects.create(project, {
include: [{
association: Projects.Colors,
include: [ ProjectColors.Sizes ]
}]
});
我再試一次,效果很好。 感謝@Sagi Rika 和@Travis Haby
其實就是這么簡單
Projects.associate = () => {
Projects.Colors = Projects.hasMany(ProjectColors, { foreignKey: 'project_id', sourceKey: 'id' });
};
ProjectColors.associate = () => {
Projects.Sizes = ProjectColors.hasMany(ProjectSizes, { foreignKey: 'project_color_id', sourceKey: 'id' });
};
並調用 create 方法如下
Projects.create(project, {
include: [{
association: Projects.Colors,
include: [{
association: Projects.Sizes,
}],
}],
})
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