[英]Swift can only see one value from firebase (retrieving data)
我只能看到我的應用程序上的用戶名而不是年齡,但我可以看到編譯器中的兩個值都不確定問題是什么。
func fetchDataa(){
// var ref: DatabaseReference!
// ref = Database.database().reference()
guard let currentUid = Auth.auth().currentUser?.uid else {return}
Database.database().reference().child("users").child(currentUid).observeSingleEvent(of: .value, with: { (snapshot) in
guard let dictionary = snapshot.value as? Dictionary<String , AnyObject> else {return}
let uid = snapshot.key
let user = User(uid:uid , dictionary: dictionary)
print(Thread.current)
print(Thread.main)
self.userAgeLabel.text = user.userage
self.user = user
self.userAgeLabel.text = user.userage
self.user = user
print(snapshot.value)
// Get user value
// let value = snapshot.value as? NSDictionary
print(dictionary)
// ...
}) { (error) in
print(error.localizedDescription)
}
//通過這種方式我將信息存儲為字典//用戶信息存儲
let userID = Auth.auth().currentUser?.uid
let userData = ["userName": userName,
"userAge ": userAge] as [String? : Any]
let ref = Database.database().reference()
ref.child("users/\(userID ?? "")").setValue(userData)
// ref.child("users").setValue(values)
}
//用戶初始化類
class User {
var username:String!
var userage:String!
var uid:String!
init(uid:String,dictionary:Dictionary){
self.uid = uid
if let username = dictionary [ "userName" ] as? String{
self.username = username
}
if let userage = dictionary [ "userAge" ] as? String{
self.userage = userage
}
}
}
}
Firebase結構:
你能試試嗎?
Database.database().reference().child("users").child(currentUid).observeEvent(of: .value, with: { (snapshot) in
if let dictionary = snapshot.value as? [String: Anyobject] {
let userAgeDictionary = dictionary["age"] as? String
print(userAgeDictionary)
這打印出年齡嗎?
你以某種方式將多余的"
圍繞userAge
財產。所以關鍵是"userAge"
包括雙引號。
要從字典中獲取該值:
if let userage = dictionary [ "\"userAge\"" ] as? String{
self.userage = userage
}
但是,您可能希望在實際數據中修復問題:在Firebase控制台中輸入密鑰時,您無需在其周圍輸入引號,因為密鑰始終是字符串。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.