如何使用內部聯接更新Codeigniter中的表？

Question

我想在查詢生成器Codeigniter中轉換此查詢Mysql

該查詢適用於mysql，但不適用於codeigniter

MySQL的

UPDATE tbl_person p
INNER JOIN tbl_family_victim f  ON  p.id_person = f.id_person
SET p.active = 0
WHERE f.id_prisoners = 32;

點火槍

public function delete_all($id_pris){
   $this->db->join('tbl_family f','p.id_person = f.id_person');
   $this->db->set('p.active', '0');
   $this->db->where('f.id_prisoners', $id_pris);
   $data_result = $this->db->update('tbl_person p');
   return  $data_result;
}

Answer 1

嘗試這個，

public function delete_all($id_pris){
   $this->db->set('p.active', '0');
   $this->db->where('f.id_prisoners', $id_pris);
   $data_result = $this->db->update('tbl_person p JOIN tbl_family f ON p.id_person = f.id_person');
   return  $data_result;
}

Answer 2

您的腳本中有分鍾錯誤，您錯過了從屬表的別名

版本1

public function delete_all($id_pris){
   $this->db->join('tbl_family f','p.id_person = f.id_person',"inner"); // you missed `f` here
   $this->db->set('p.active', '0');
   $this->db->where('f.id_prisoners', $id_pris);
   $data_result = $this->db->update('tbl_person p');
   return  $data_result;
}

這應該工作正常。

版本2

$this->db->set('p.active', '0');
$this->db->where('f.id_prisoners', $id_pris);
$this->db->where('p.id_person = f.id_person')
$data_result = $this->db->update('tbl_family as f, tbl_person as p');
return $data_result;

版本3

$sql = "
UPDATE tbl_person p
INNER JOIN tbl_family_victim f  ON  p.id_person = f.id_person
SET p.active = 0
WHERE f.id_prisoners = $id_pris";
$this->db->query($sql);

版本4

$this->db->set('p.active', '0');
$this->db->where('f.id_prisoners', $id_pris);
$data_result = $this->db->update('tbl_family as f JOIN  tbl_person as p ON p.id_person = f.id_person');
return $data_result;