在Python中將JSON解析為平面文件

Question

我想讀一個JSON格式文件，其中key始終不相同，並將其轉換為平面文件以供進一步處理。 我嘗試找到一個解決方案，但沒有任何效果。

以下是示例JSON數據。

{
    "Meta Data": {
        "1. Information": "Intraday (5min) open, high, low, close prices and volume",
        "2. Symbol": "MSFT",
        "3. Last Refreshed": "2019-04-15 13:05:00",
        "4. Interval": "5min",
        "5. Output Size": "Compact",
        "6. Time Zone": "US/Eastern"
    },
    "Time Series (5min)": {
        "2019-04-15 13:05:00": {
            "1. open": "120.8250",
            "2. high": "120.9400",
            "3. low": "120.7800",
            "4. close": "120.9275",
            "5. volume": "152975"
        },
        "2019-04-15 13:00:00": {
            "1. open": "120.8900",
            "2. high": "120.8900",
            "3. low": "120.8000",
            "4. close": "120.8250",
            "5. volume": "156065"
        },
        "2019-04-15 12:55:00": {
            "1. open": "120.8600",
            "2. high": "120.9000",
            "3. low": "120.8450",
            "4. close": "120.8950",
            "5. volume": "53450"
        },
    }
}       

我想將其轉換為以下格式

2019-04-15 13:05:00,120.8250,120.9400,120.7800,120.9275,152975
2019-04-15 13:00:00,120.8900,120.8900,120.8000,120.8250,156065
2019-04-15 12:55:00,120.8600,120.9000,120.8450,120.8950,53450

我試過下面的東西。

url = URL from where data is coming in JSON format.
response = requests.get(url, headers=header, cookies=cookies)
dic = json.loads(response.content)
len_of_timeseries = len(dic["Time Series (1min)"])
key_len = {}
for k in dic["Time Series (1min)"]:
  print (dic["Time Series (1min)"][k])
f = open(symbolFile,"w") 
f.write(write the file here)
f.close

以上打印聲明是如下打印詳細信息。 根本不是閱讀日期字段。

{'1. open': '11689.7998', '2. high': '11690.6504', '3. low': '11689.3496', '4. close': '11689.5996', '5. volume': '0'}
{'1. open': '11687.2500', '2. high': '11690.2002', '3. low': '11686.6504', '4. close': '11689.3496', '5. volume': '0'}

任何幫助將不勝感激。

謝謝

Answer 1

for循環中的k值包含您要查找的日期：

for k in dic["Time Series (1min)"]:
    print (dic["Time Series (1min)"][k])
    print(k) # this will print the date

Answer 2

dic = {
    "Meta Data": {
        "1. Information": "Intraday (5min) open, high, low, close prices and volume",
        "2. Symbol": "MSFT",
        "3. Last Refreshed": "2019-04-15 13:05:00",
        "4. Interval": "5min",
        "5. Output Size": "Compact",
        "6. Time Zone": "US/Eastern"
    },
    "Time Series (5min)": {
        "2019-04-15 13:05:00": {
            "1. open": "120.8250",
            "2. high": "120.9400",
            "3. low": "120.7800",
            "4. close": "120.9275",
            "5. volume": "152975"
        },
        "2019-04-15 13:00:00": {
            "1. open": "120.8900",
            "2. high": "120.8900",
            "3. low": "120.8000",
            "4. close": "120.8250",
            "5. volume": "156065"
        },
        "2019-04-15 12:55:00": {
            "1. open": "120.8600",
            "2. high": "120.9000",
            "3. low": "120.8450",
            "4. close": "120.8950",
            "5. volume": "53450"
        },
    }
}

。

items = dic["Time Series (5min)"]

for dt, v in items.items():
    row = [dt] # date time
    row += v.values()
    print(','.join(row))

結果

2019-04-15 13:05:00,120.8250,120.9400,120.7800,120.9275,152975
2019-04-15 13:00:00,120.8900,120.8900,120.8000,120.8250,156065
2019-04-15 12:55:00,120.8600,120.9000,120.8450,120.8950,53450

但它可能不會尊重排序。
如果您知道鍵"1. open" ， "2. high"等，那么最好使用它們來保持秩序。

for dt, v in items.items():
    row = [dt, v["1. open"], v["2. high"], v["3. low"], v["4. close"], v["5. volume"]]
    print(','.join(row))