[英]How do I assign a boolean from second block of code to the first block of indentation in python?
當我在第5個塊中分配out_of_marks_limit = True
時,我希望if語句的第一個塊為“True”,並且我不希望代碼循環或再詢問用戶。
在其他編程語言中,縮進用於使程序看起來很好。 但是因為python只檢查第一個塊到相同縮進的條件,所以我不能將2個代碼塊的布爾值分配給第一個塊。 這就是我想說的。
我是一名中級程序員,這個程序僅用於練習目的。
a = int(input("Enter no. of subjects: "))
count = 1
d = 0
out_of_marks_limit = False #I want the out_of_limit to be True
if a <= 10:
if not out_of_marks_limit:
if count <= a:
for c in range(a):
b = float(input("Enter mark of subject " + str(count) + ": "))
if b <= 100: #If this condition went false then it will skip to else statement
d += b
count += 1
if count > a:
cal = round(d/a, 2)
print("Your percentage is " + str(cal) + "%")
else:
out_of_marks_limit = True #So this boolean value should passed to the first line of code
print("Marks enter for individual subject is above 100")
else:
print("Subject limit exceeded")
我希望輸出打印(“單個主題的標記輸入超過100”),如果out_of_marks_limit為True並且不想再循環
我認為您可以使用while循環來檢查out_of_marks_limit條件:
a = int(input("Enter no. of subjects: "))
count = 1
d = 0
out_of_marks_limit = False #I want the out_of_limit to be True
while not out_of_marks_limit:
if a <= 10:
if not out_of_marks_limit:
if count <= a:
for c in range(a):
b = float(input("Enter mark of subject " + str(count) + ": "))
if b <= 100: #If this condition went false then it will skip to else statement
d += b
count += 1
if count > a:
cal = round(d/a, 2)
print("Your percentage is " + str(cal) + "%")
else:
out_of_marks_limit = True #So this boolean value should passed to the first line of code
print("Marks enter for individual subject is above 100")
else:
print("Subject limit exceeded")
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