RegEx用於字母數字文本字符串，最多可使用特殊模式

Question

我有一個具有特定格式的字符串列表，只需要其中的一部分即可。

輸入項

my_list = ['The Price Is Right S47E141 720p WEB x264-W4F', 'Breakthrough-The Ideas That Changed the World S01E01 480p x264-mSD',
'The Kid Who Would Be King 2019 DVDR-JFKDVD', 'American Housewife S03E18 Phone Free Day 1080p AMZN WEB-DL DDP5 1 H 264-NTb',
'VICE News Tonight 2019 04 16 720p AMZN WEB-DL DDP2 0 H 264-monkee','The Flash 2014 S05E18 Godspeed 720p AMZN WEB-DL DDP5 1 H 264-NTb',
'The Rachel Maddow Show 2019 04 16 720p MNBC WEB-DL AAC2 0 x264-BTW','Lets Make A Deal 2009 S10E142 XviD-AFG']

正則表達式嘗試：

try:
    try:
        def get_rls(t):
            w = re.match(".*\d{4} \d{2} \d{2} ", t)
            # w = re.match(".*S\d+E\d+", t)
            if not w: raise Exception("Error For Regular Expression")
            return w.group(0)

        regular_case = [my_list ]
        for w in regular_case:
            Regular_part = get_rls(w)
            print(">>>> Movie Regular Part contains Year/Mon/Day : ", Regular_part)         
    except:
        try:
            def get_rls(t):
                # w = re.match(".*\d ", t)
                w = re.match(".*S\d+E\d+", t)
                if not w: raise Exception("Error For Regular Expression")
                return w.group(0)


            regular_case = [my_list ]
            for w in regular_case:
                Regular_part = get_rls(w)
                print(">>>> Movie Regular Part contains S0E0 : ", Regular_part)             

        except:
            def get_rls(t):
                w = re.match(".*\d{4} ", t)
                # w = re.match(".*S\d+E\d+", t)
                if not w: raise Exception("Error For Regular Expression")
                return w.group(0)


            regular_case = [my_list ]
            for w in regular_case:
                Regular_part = get_rls(w)
                print(">>>> Movie Regular Part contains Year : ", Regular_part)

except:
    print(">>>> Weard Release Name! Pass the Regular part ")
    Regular_part = my_list 

問題是，我的正則表達式代碼只能獲取一個元素並決定使用哪個RegEx有用並打印正則表達式，而我需要RegEx代碼能夠獲取列表並處理每個單個元素，例如獲取第一個元素和決定哪一個是好的。

最好的結果應類似於以下列表：

my_list = ['The Price Is Right S47E141', 'Breakthrough-The Ideas That Changed the World S01E01',
'The Kid Who Would Be King 2019 DVDR-JFKDVD', 'American Housewife S03E18 ',
'VICE News Tonight 2019 04 16','The Flash 2014 S05E18',
'The Rachel Maddow Show 2019 04 16 ','Lets Make A Deal 2009 S10E142']

Answer 1

此RegEx並非完全正確的答案，但也許它將幫助您找出處理文本輸入的一般方法。 也許RegEx並不是解決此問題的最佳方法：

^.+?(?:[SE0-9]+)|(?:\s[A-Z]{4}\-[A-Z]{1,})|(?:.+[0-9]{4}\s[0-9]{2}\s[0-9]{2})|(?:\s[SE0-9]{6,10})

SE模式和date模式對於此RegEx很簡單。 你可能會面臨的問題是隨機年，如2014 ， 2009和2019 ，你可能會考慮。