如何從單個表中對多個行進行分組並獲取給定范圍內的所有記錄

Question

我希望在我宿舍的桌子上給定價格范圍內的所有宿舍。 價格存儲在四個不同的行中，如價格一股，價格二股，價格三股，價格更多份額，

public function actionNearbyHostel($min,$max,$types,$lat,$long){   
    $latitude = $lat;
    $longitude = $long;
    $type = $types;
    $max_price = (int)$max;
    $min_price = (int)$min;
    $hostels = Hostels::find ()->select("*,(6371 * 
        acos(cos(radians({$latitude}))* 
        cos(radians(`lat`)) * cos(radians(`log`) - radians({$longitude})) + 
        sin(radians({$latitude})) * sin(radians(`lat`)))) AS distance")
            ->having("distance<:distance")
            ->addParams([ 
                ':distance' => 5 
            ])->where([
                'status' => Hostels::ACTIVE,
                'type' => $type
            ])->andWhere(['between','price_one_share',$min_price,$max_price])
    ->all();
    return $this->render('filterhostel',[
        'hostels' => $hostels,
    ]);
} 

這是我已經寫過的行動

andWhere(['between','price_one_share',$min_price,$max_price])

像這樣，我想包括剩下的三行並得到我的結果。

這是我的表行圖像http://www.clipular.com/posts/4991398571671552?k=Lud1W4LGJe5hSxOsl2ao7VOGguI

Answer 1

做了一些功課后，我找到了答案

 public function actionNearbyHostel($min,$max,$types,$lat,$long){   
    $latitude = $lat;
    $longitude = $long;
    $type = $types;
    $max_price = (int)$max;
    $min_price = (int)$min;
    $hostels = Hostels::find ()->select("*,(6371 * acos(cos(radians({$latitude}))* 
    cos(radians(`lat`)) * cos(radians(`log`) - radians({$longitude})) + 
    sin(radians({$latitude})) * sin(radians(`lat`)))) AS distance")
    ->having("distance<:distance")
    ->addParams([ 
    ':distance' => 5 
    ])->where([
    'status' => Hostels::ACTIVE,
    'type' => $type
    ])->andWhere(['or',
    ['between','price_one_share',$min_price,$max_price],
    ['between','price_two_share',$min_price,$max_price],
    ['between','price_three_share',$min_price,$max_price],
    ['between','price_more_share',$min_price,$max_price]
    ])
    ->all();
    return $this->render('filterhostel',[
        'hostels' => $hostels,
    ]);
}