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[英]jQuery ajax not displaying data from php to a table with angularjs and json
[英]Displaying JSON in table with JQuery
之前,單擊了一個按鈕,從Django視圖中檢索模板和上下文數據,並按如下所示進行渲染:
<tbody>
{% for card_holder in card_holders %}
<tr>
<td>{{ card_holder.first_name }}</td>
<td>{{ card_holder.last_name }}</td>
<td>{{ card_holder.email }}</td>
<td>{{ card_holder.cell_phone }}</td>
<td>{{ card_holder.direct_tel }}</td>
<td>{{ card_holder.status }}</td>
{% if card_holder.slug %}
<td><a target="_blank" href="{% url 'detail' slug=card_holder.slug %}">View Card</a></td>
{% else %}
<td>No slug available</td>
{% endif %}
</tr>
{% endfor %}
</tbody>
我添加了一個視圖來檢索所有這些數據而不渲染頁面,並且響應如下所示:
[{
"id": 18,
"avatar": null,
"first_name": "Walter",
"last_name": "Kuselli",
"title": "Actuary",
"cell_phone": "+27768943437",
"direct_tel": null,
"email": "walter@walter.co.za",
"website_url": null,
"address": null,
"linkedin_url": null,
"facebook_url": null,
"twitter_url": null,
"instagram_url": null,
"pinterest_url": null,
"status": "demo",
"slug": "57139752478236",
"name_font_size": 20,
"title_font_size": 15,
"email_font_size": 15,
"address_font_size": 15,
"created_at": "2019-02-20T17:38:43.261441",
"updated_at": "2019-02-20T17:38:43.261508",
"import_id": null,
"send_id": false,
"next_renewal_date": "2020-02-20T17:54:05.554508",
"paid_id": true,
"transaction_id": 17,
"branch": 3,
"user": 19
},
{
"id": 19,
"avatar": null,
"first_name": "Wally Kuselli",
"last_name": "Kusellli",
"title": "Actuary",
"cell_phone": "+27788949437",
"direct_tel": null,
"email": "walter@walter.co.za",
"website_url": null,
"address": null,
"linkedin_url": null,
"facebook_url": null,
"twitter_url": null,
"instagram_url": null,
"pinterest_url": null,
"status": "demo",
"slug": "3838834981253446",
"name_font_size": 20,
"title_font_size": 15,
"email_font_size": 15,
"address_font_size": 15,
"created_at": "2019-02-20T17:38:50.032723",
"updated_at": "2019-02-20T17:38:50.032791",
"import_id": null,
"send_id": false,
"next_renewal_date": null,
"paid_id": false,
"transaction_id": null,
"branch": 3,
"user": 20
}]
在這樣的表中顯示JSON的最佳方法是什么? 我已經看到了這樣的答案:
$.getJSON("http://10.0.2.2:8080/v1/service/1",
function (data) {
$.each(data, function (key, val) {
var tr = $('<tr></tr>');
$.each(val, function (k, v) {
$('<td>' + v + '</td>').appendTo(tr);
});
tr.appendTo('#display');
});
});
但這假設響應如下所示:
data = {
"key_one": "value_one",
"key_two": "value_two",
"key_three": "value_three"
}
參見下面的實現。 有用。
data = [{ "id": 18, "avatar": null, "first_name": "Walter", "last_name": "Kuselli", "title": "Actuary", "cell_phone": "+27768943437", "direct_tel": null, "email": "walter@walter.co.za", "website_url": null, "address": null, "linkedin_url": null, "facebook_url": null, "twitter_url": null, "instagram_url": null, "pinterest_url": null, "status": "demo", "slug": "57139752478236", "name_font_size": 20, "title_font_size": 15, "email_font_size": 15, "address_font_size": 15, "created_at": "2019-02-20T17:38:43.261441", "updated_at": "2019-02-20T17:38:43.261508", "import_id": null, "send_id": false, "next_renewal_date": "2020-02-20T17:54:05.554508", "paid_id": true, "transaction_id": 17, "branch": 3, "user": 19 }, { "id": 19, "avatar": null, "first_name": "Wally Kuselli", "last_name": "Kusellli", "title": "Actuary", "cell_phone": "+27788949437", "direct_tel": null, "email": "walter@walter.co.za", "website_url": null, "address": null, "linkedin_url": null, "facebook_url": null, "twitter_url": null, "instagram_url": null, "pinterest_url": null, "status": "demo", "slug": "3838834981253446", "name_font_size": 20, "title_font_size": 15, "email_font_size": 15, "address_font_size": 15, "created_at": "2019-02-20T17:38:50.032723", "updated_at": "2019-02-20T17:38:50.032791", "import_id": null, "send_id": false, "next_renewal_date": null, "paid_id": false, "transaction_id": null, "branch": 3, "user": 20 } ] var draw = function(data) { $.each(data, function(key, val) { var tr = $('<tr></tr>'); $.each(val, function(k, v) { $('<td>' + v + '</td>').appendTo(tr); }); tr.appendTo('#display'); }); } draw(data)
td { border: 1px solid black; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.0.3/jquery.min.js"></script> <table id="display"> </table>
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