[英]SQL Query Join two Queries with Sum()
我知道這對您的sql人員來說很簡單,但是我試圖將兩個簡單的查詢合並為一個。 從代碼中可以明顯看出job.ActiveJob.ID = job.EstimateTbl.ID_Job。
我正在嘗試獲取:id,JobName,sum(itemAmount)
謝謝你的幫助。
SELECT a.id, a.JobName
FROM job.ActiveJobsTbl AS a
WHERE a.ID = '100'
SELECT SUM(itemAmount)
FROM job.EstimateTbl
WHERE ID_Job = '100'
您可以通過ON E.ID_Job = A.ID
JOIN
表,並使用GROUP BY
獲取SELECT
的值
SELECT A.id, A.JobName, SUM(E.itemAmount) AS Amount
FROM job.ActiveJobsTbl AS A
INNER JOIN job.EstimateTbl E ON E.ID_Job = A.ID
WHERE A.ID = '100'
GROUP BY A.id, A.JobName;
使用LEFT JOIN
SELECT a.id, a.JobName,EstimateTbl.itemAmount
FROM job.ActiveJobsTbl AS a
left join
(
SELECT SUM(itemAmount) itemAmount,ID_Job
FROM job.EstimateTbl
group by ID_Job
) EstimateTbl on EstimateTbl.ID_Job = a.ID
WHERE a.ID = '100'
您可以使用APPLY
:
select a.id, a.JobName, t.itemAmount
from job.ActiveJobsTbl AS a OUTER APPLY
(SELECT SUM(t.itemAmount) AS itemAmount
FROM job.EstimateTbl AS t
WHERE t.ID_Job = a.ID
) t
WHERE a.ID = 100;
嘗試這個:
SELECT A.id, A.JobName, SUM(E.itemAmount) AS Amount
FROM job.ActiveJobsTbl AS A
INNER JOIN job.EstimateTbl E ON E.ID_Job = A.ID
WHERE A.ID = '100'
GROUP BY A.id, A.JobName;
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