[英]trying to add data and query a mysql database using sqlobject and python 3
我的代碼提出了一個異常,如下所示。 我很確定問題出在表關系的定義上。 我嘗試了多種選擇,它們會給出不同的錯誤:-(
我擁有一個可以具有一個或多個MacAddress的許可證,如下所示:
class MacAddress(sqlobject.SQLObject):
# noinspection PyPep8Naming,PyClassHasNoInit
class sqlmeta:
table = "mac_address_table"
mac_address = sqlobject.StringCol(unique=True, length=50)
license = sqlobject.ForeignKey('License', default=None)
class License(sqlobject.SQLObject):
# noinspection PyPep8Naming,PyClassHasNoInit
class sqlmeta:
table = "license_table"
user_name = sqlobject.StringCol(unique=True, length=50)
mac_addresses = sqlobject.MultipleJoin('MacAddress')
@staticmethod
def create(user_name, mac_address):
lic = License(user_name=user_name)
mac = MacAddress.get(mac_address)
lic.add_mac_address(mac)
return lic
def add_mac_address(self, mac_address):
mac_address.license = self
@staticmethod
def is_valid(user_name, mac_address):
query = License.selectBy(user_name=user_name)
found = False
if query.count() != 0:
lic = query.getOne()
# Here is where I am having a problem:
for mac in lic.mac_addresses:
if mac.mac_address == mac_address:
found = True
break
if found:
return True
return False
當我嘗試像這樣測試許可證時:
lic.is_valid(user_name="Fred", mac_address="1234"),
我在這一行收到錯誤:對於lic.mac_addresses中的mac:
我收到以下錯誤:
sqlobject.dberrors.OperationalError: Unknown column 'license_table_id' in 'where clause'
我的數據庫中有以下表格:
mac_address_table:
+----------------------+---------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+----------------------+---------+------+-----+---------+-------+
| license_table_id | int(11) | NO | | NULL | |
| mac_address_table_id | int(11) | NO | | NULL | |
+----------------------+---------+------+-----+---------+-------+
license_table:
+-----------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+-------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| user_name | varchar(50) | YES | UNI | NULL | |
+-----------+-------------+------+-----+---------+----------------+
mac_address_table_license_table:
+----------------------+---------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+----------------------+---------+------+-----+---------+-------+
| license_table_id | int(11) | NO | | NULL | |
| mac_address_table_id | int(11) | NO | | NULL | |
+----------------------+---------+------+-----+---------+-------+
這是數據庫的內容:
select * from license_table; select * from mac_address_table; select * from license_table_mac_address_table;
+----+-----------+----------+---------------------+
| id | user_name | password | created |
+----+-----------+----------+---------------------+
| 1 | Fred | xxx | 2019-04-29 17:59:47 |
+----+-----------+----------+---------------------+
1 row in set (0.00 sec)
+----+-------------+------------+
| id | mac_address | license_id |
+----+-------------+------------+
| 1 | 1234 | 1 |
+----+-------------+------------+
1 row in set (0.00 sec)
+------------------+----------------------+
| license_table_id | mac_address_table_id |
+------------------+----------------------+
| 1 | 1 |
+------------------+----------------------+
SQLObject
需要知道SQLObject
列。 幫忙一點:
class License(sqlobject.SQLObject):
class sqlmeta:
table = "license_table"
user_name = sqlobject.StringCol(unique=True, length=50)
mac_addresses = sqlobject.MultipleJoin('MacAddress', joinColumn='license_id')
這里的關鍵部分是joinColumn='license_id'
。
PS。 與您的問題沒有直接關系:
if query.count() != 0:
lic = query.getOne()
在這里,您運行查詢兩次。 我建議優化:
try:
lic = query.getOne()
except sqlobject.SQLObjectNotFound:
return False
else:
for mac in lic.mac_addresses:
…
我似乎已修復它:
class MacAddress(sqlobject.SQLObject):
# noinspection PyPep8Naming,PyClassHasNoInit
class sqlmeta:
table = "mac_address_table"
value = sqlobject.StringCol(unique=True, length=50)
license = sqlobject.ForeignKey('License', default=None)
class License(sqlobject.SQLObject):
# noinspection PyPep8Naming,PyClassHasNoInit
class sqlmeta:
table = "license_table"
user_name = sqlobject.StringCol(unique=True, length=50)
mac_addresses = sqlobject.MultipleJoin('MacAddress', joinColumn='license_id')
@staticmethod
def create(user_name, mac_address):
lic = License(user_name=user_name)
lic.add_mac_address(mac_address=mac_address)
return lic
def add_mac_address(self, mac_address):
mac_address.license = self
@staticmethod
def is_valid(user_name, mac_str):
query = License.selectBy(user_name=user_name)
found = False
if query.count() != 0:
lic = query.getOne()
for mac in lic.mac_addresses:
if mac_str == mac.value:
found = True
break
if found:
return True
return False
現在工作正常:
def test_license():
mac_address = MacAddress(value="123")
lic = License.create(user_name="Fred", mac_address=mac_address)
mac_address = MacAddress(value="2468")
lic.add_mac_address(mac_address=mac_address)
print(lic.is_valid(user_name="Fred", mac_str=mac_address.value))
print(lic.is_valid(user_name="Fred", mac_str="3456"))
我不知道要做什么來糾正此錯誤,除非這有點像在MacAddress中重寫SQLObject get方法之類的事情。謝謝您的幫助。
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