[英]How can I create a deadlock with Rust?
我想知道如何創建死鎖。
我試圖在 Rust 中創建一個有死鎖的程序。
如何創建一個?
一個非常簡單的變體:
use std::sync::{Arc, Mutex};
fn main() {
let data = Arc::new(Mutex::new(0));
let d1 = data.lock();
let d2 = data.lock(); // cannot lock, since d1 is still active
}
與其他編程語言一樣,Rust 可能會出現無聲殺手死鎖。
如果某個鎖定互斥體的線程正在等待另一個,這不是一個好兆頭:如果另一個不能來,第一個互斥體將永遠不會被釋放。
use std::{sync::{Mutex, MutexGuard}, thread};
use std::thread::sleep;
use std::time::Duration;
use lazy_static::lazy_static;
lazy_static! {
static ref MUTEX1: Mutex<i64> = Mutex::new(0);
static ref MUTEX2: Mutex<i64> = Mutex::new(0);
}
fn main() {
// Spawn thread and store handles
let mut children = vec![];
for i_thread in 0..2 {
children.push(thread::spawn(move || {
for _ in 0..1 {
// Thread 1
if i_thread % 2 == 0 {
// Lock mutex1
// No need to specify type but yes create a dummy variable to prevent rust
// compiler from being lazy
let _guard: MutexGuard<i64> = MUTEX1.lock().unwrap();
// Just log
println!("Thread {} locked mutex1 and will try to lock the mutex2, after a nap !", i_thread);
// Here I sleep to let Thread 2 lock mutex2
sleep(Duration::from_millis(10));
// Lock mutex 2
let _guard = MUTEX2.lock().unwrap();
// Thread 2
} else {
// Lock mutex 1
let _guard = MUTEX2.lock().unwrap();
println!("Thread {} locked mutex2 and will try to lock the mutex1", i_thread);
// Here I freeze !
let _guard = MUTEX1.lock().unwrap();
}
}
}));
}
// Wait
for child in children {
let _ = child.join();
}
println!("This is not printed");
}
哪些輸出
Thread 0 locked mutex1 and will try to lock the mutex2, after a nap !
Thread 1 locked mutex2 and will try to lock the mutex1
然后永遠等待
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