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[英]How to convert scala.collection.Map<Object, Object> to Java's Map<Integer, Integer>?
[英]convert JavaObject `scala.collection.Map<Object,RDD<?>>` to python dictionary
在pyspark中,調用getPersistentRDDs getPersistentRDDs()
Java sparkContext方法將返回scala.collection.Map<Object,RDD<?>>
JavaObject實例。
from pyspark.sql import SparkSession
from pyspark import StorageLevel
spark = SparkSession.builder.master('yarn').getOrCreate()
sc = spark.sparkContext
df = spark.range(0, 25000000, 1)
df.persist(StorageLevel.MEMORY_ONLY)
df.limit(1).count()
sc._jsc.sc().getPersistentRDDs()
返回JavaObject id=o477
如何將scala.collection.Map<Object,RDD<?>>
的scala.collection.Map<Object,RDD<?>>
轉換為python字典?
from pyspark import RDD
scala_map = sc._jsc.sc().getPersistentRDDs()
py_dict = {e._1(): RDD(e._2().toJavaRDD(), sc) for e in [scala_map.toList().apply(i) for i in range(scala_map.size())]}
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