如何在PHP-MySQL中聯接兩個表，該表與第二個表中的ID匹配並仍在表1中顯示特定記錄？

Question

我有兩個表（帳戶和餐廳），如何顯示兩個表中的所有記錄，但排除一些記錄？

table: account
+-------+----------+------------+
| uid   | name     | role       |
+-------+----------+------------+
|  1    | John     | Admin      |
|  2    | Steve    | Resto_Owner|
|  3    | Bill     | Customer   |
+-------+----------+------------+

table: restaurant
+--------+----------+------------+
|resto_id|  uid     | resto_name |
+--------+----------+------------+
|  1     |   2      |Steve Resto |
+--------+----------+------------+


**This is my Desired Output:** 
+-------+----------+------------+--------------+
| uid   | name     | role       | resto_name   |
+-------+----------+------------+--------------+
|  1    | John     | Admin      |              |
|  2    | Steve    | Resto_Owner| Steve Resto  |
+-------+----------+------------+--------------+

我想以角色admin和resto_owner顯示這兩個表中的記錄。 但如果角色為resto_owner，則還顯示resto_name；如果為admin，則顯示空白；如果客戶，則不顯示

我嘗試使用INNER JOIN，但它僅顯示： 2 Steve Resto_Owner Steve Resto ，並且不顯示管理記錄：

先感謝您 ：）

Answer 1

與條件一起使用左聯接

 SELECT account_table.uid, account_table.name, account_table.role, restaurant_table.resto_name 
    FROM account account_table LEFT JOIN restaurant restaurant_table
    ON restaurant_table.uid = account_table.uid 
    WHERE account_table.role <> 'Customer' ORDER BY account_table.uid ASC

https://www.w3schools.com/sql/sql_join_left.asp中的更多內容