為什么我的if和elif語句一次只能用於一個按鈕？

Question

我讓程序顯示存儲在json文件中的按鈕列表。 與當前時間time.time()和用戶輸入的delay相比，我具有每個按鈕的存儲時間honey 。

由於某些原因，條件條件僅在有一個按鈕時才起作用。 一旦添加了其他按鈕，程序將第一個按鈕變為綠色以指示其為早，而新按鈕變為黃色以指示其為早期。 新按鈕變成紅色后，第一個按鈕也變成紅色。

我已經為程序計時，並且程序在正確的時間運行。 為什么會有這個問題，我該如何解決？ 碼：

class MainApp(App):
    def build(self): # build() returns an instance
        self.store = JsonStore("streak.json") # file that stores the streaks:
        Clock.schedule_interval(self.check_streak, 1/30.)

        return presentation

    def check_streak(self, dt):

        for child in reversed(self.root.screen_two.ids.streak_zone.children):
            honey = float(child.id)

            with open("streak.json", "r") as read_file:
                data = json.load(read_file)

            for value in data.values():
                if value['delay'] is not None:
                    delay = int(value['delay'])

                    if delay > time.time() < honey: # early (yellow)
                        child.background_normal = ''
                        child.background_color = [1, 1, 0, 1]

                    elif delay > time.time() > honey: # on time (green)
                        child.background_normal = ''
                        child.background_color = [0, 1, 0, 1]


                    elif delay < time.time() > honey: # late (red)
                        child.background_normal = ''
                        child.background_color = [1, 0, 0, 1]

def display_btn(self):
        # display the names of the streaks in a list on PageTwo
        with open("streak.json", "r") as read_file:
            data = json.load(read_file)

        for value in data.values():
            if value['delta'] is not None:
                print(f"action={value['action']}, delta={value['delta']}, grace={value['delay']}")
                streak_button = StreakButton(id=str(value['delta']), text=value['action'],
                                            on_press=self.third_screen, size=(400,50),
                                            size_hint=(None,None))
                self.root.screen_two.ids.streak_zone.add_widget(streak_button)

total = ((int(self.streak.day) * 86400) + (int(self.streak.hour) * 3600) +
                    (int(self.streak.minute) * 60)) # convert into seconds

            self.current_time = time.time()
            self.count = self.current_time + total
            grace = (int(self.streak.delay) * 60) + self.count # aka delay

            parsed = True

            # delete later just used to test
            print("[seconds:", total,']' , "[action:", self.streak.action,']',
                 "[grace:", grace,']')

            # store streak attributes inside "streak.json"
            self.store.put(self.streak.action, action=self.streak.action,
                          delay=grace, seconds=total,
                          score=0, delta=self.count)

streak.json文件： {"one": {"action": "one", "delay": 1557095861.2131674, "seconds": 60, "score": 0, "delta": 1557095801.2131674}, "two": {"action": "two", "delay": 1557096131.7338686, "seconds": 60, "score": 0, "delta": 1557096071.7338686}}

Answer 1

它僅適用於一個按鈕，因為if...elif語句在for循環之外。

解

將if...elif塊移至if value['delay'] is not None: for循環內的塊。

片段

def check_streak(self, dt):

    for child in reversed(self.root.screen_two.ids.streak_zone.children):
        honey = float(child.id)

        with open("streak.json", "r") as read_file:
            data = json.load(read_file)

        for value in data.values():
            if value['delay'] is not None:
                delay = int(value['delay'])

                # fix for later
                if delay > time.time() < honey: # early (yellow)
                    child.background_normal = ''
                    child.background_color = [1, 1, 0, 1]

                elif delay > time.time() > honey: # on time (green)
                    child.background_normal = ''
                    child.background_color = [0, 1, 0, 1]

                elif delay < time.time() > honey: # late (red)
                    child.background_normal = ''
                    child.background_color = [1, 0, 0, 1]

Answer 2

問題是有兩個循環導致我的數據不匹配。 我需要能夠遍歷按鈕對象並僅對每個對象使用正確的json文件字典條目，或者遍歷json文件並僅修改相應的子對象。 我決定使用前者。

我設置了代碼，以便在streak_zone name = child.text中的每個孩子name = child.text

然后，我將json文件中的每個鍵與按鈕的名稱（也就是child

如果鍵的名稱等於name那么我們得到嵌套鍵delay的值

新代碼：

def check_streak(self, dt):

        for child in reversed(self.root.screen_two.ids.streak_zone.children):
            honey = float(child.id)
            name = child.text


            with open("streak.json", "r") as read_file:
                data = json.load(read_file)


            for key in data.keys():
                if key == name:
                    delay = data.get(key, {}).get('delay')


                if delay > time.time() < honey: # early (yellow)
                    child.background_normal = ''
                    child.background_color = [1, 1, 0, 1]

                elif delay > time.time() > honey: # on time (green)
                    child.background_normal = ''
                    child.background_color = [0, 1, 0, 1]


                elif delay < time.time() > honey: # late (red)
                    child.background_normal = ''
                    child.background_color = [1, 0, 0, 1]