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[英]move uploaded image into folder in php(move_uploaded_file() function)
[英]PHP move_uploaded_file() only moves the last picture to the folder
我有一個表單,盡管我想上傳多個圖像並將其存儲在文件夾中,但是我的程序僅存儲最后選擇的圖像。
我的表格:
<form method="POST" action="server.php" enctype="multipart/form-data">
<input type="file" name="pictures[]" multiple>
<button class="btn btn-success btn-block" name="add">ADD</button>
</form>
我的PHP代碼:
$images = $_FILES['pictures'];
$image_names = $images['name'];
$image_tmpnames = $images['tmp_name'];
foreach($image_names as $image_name){
$foto = 'images/' . $image_name;
foreach($image_tmpnames as $image_tmpname){
move_uploaded_file($image_tmpname,$foto);
}
}
如何解決此問題,以便將所有圖片都移到“圖像”文件夾中?
不要使用嵌套循環。 您要並行處理兩個數組,而不是作為叉積。
foreach ($image_names as $i => $image_name) {
$image_tmpname = $image_tmpnames[$i];
$foto = 'images/' . $image_name;
move_uploaded_file($image_tmpname,$foto);
}
也許嘗試其他循環,並設置距離路徑。
我精心編寫了可以在您的解決方案中實現的代碼:
$arquivo = isset($_FILES['img']) ? $_FILES['img'] : FALSE;
for ($controle = 0; $controle < count($arquivo['name']); $controle++){
$destino = $diretorio."/".$arquivo['name'][$controle];
if(move_uploaded_file($arquivo['tmp_name'][$controle], $destino)){
echo "Upload sucess<br>";
}else{
echo "Erro upload";
}
}
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