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[英]Oracle SQL query to select only records with date earliest on Department Table
[英]Oracle SQL Select Date Time with Earliest Time
我有一個查詢返回此
我要返回這一點,選擇當天的最早時間
到目前為止,這是我的查詢--- MIN(I.CREATIONDATE)
確實返回了我想要的日期時間格式,我希望MIN
選擇最早的時間。
SELECT TO_CHAR(MIN(I.INCIDENTID)) AS "Incident ID",
MIN(I.CREATIONDATE) AS "Creation Date",
TO_CHAR(I.CREATIONDATE,'MM-DD-YYYY') AS "Date",
TRIM(MO.DOMAINUSERNAME) AS "Login ID",
TRIM(M.MESSAGESUBJECT) AS "Email Subject"
FROM MESSAGE M
JOIN INCIDENT I
ON M.MESSAGESOURCE = I.MESSAGESOURCE
AND M.MESSAGEID = I.MESSAGEID
AND M.MESSAGEDATE = I.MESSAGEDATE
JOIN MESSAGEORIGINATOR MO
ON M.MESSAGEORIGINATORID = MO.MESSAGEORIGINATORID
GROUP BY TO_CHAR(I.CREATIONDATE,'MM-DD-YYYY'),
TRIM(MO.DOMAINUSERNAME),
TRIM(M.MESSAGESUBJECT)
使用row_number()
with CTE as
(
select t1.*,
row_number() over (partition by trunc(creation_date) order by creation_date) rn
from Mytable t1
)
select *
from CTE
where rn = 1
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