如何檢查兩個數組是否相同或不同

Question

我需要檢查兩個數組是否相同或不同。 testScores是二維的，而answerKey是一維的。

我試圖做到這一點：

if (testScores[student][20] != answerKey[0]){
  cout<<"Right
  cout<<endl;
} else {
  cout<<"Not working";
  cout<<endl;
}

但仍然行不通

if (testScores == answerKey){
  sum +=1;
  cout<<"Sum: "<<sum;
} else if (testScores != answerKey) {
  sum -= 1;
  cout<<"Sum: "<<sum;
} else(testScores = ' ')
  sum += 0;
cout<<"Sum: "<<sum;
}

Answer 1

如何檢查兩個數組是否相同或不同

您可以使用std :: equal 。 這就是該功能的目的，以測試兩個范圍（在您的情況下為數組）是否相同或不同。

這是一個僅使用一名學生的示例，但是兩個答案鍵每個僅包含5個答案。 請擴展它以適應實際的學生人數和答案。

#include <algorithm>
#include <iostream>

int main()
{
   const int numStudents = 1;
   const int numScores = 5;
   int testScores[numStudents][numScores] = {{10,20,30,40,50}};
   int answerKey[] = {10,20,30,40,50};
   int answerKey2[] = {10,20,30,40,60};

   for (int i = 0; i < numStudents; ++i)
   {
      if (std::equal(&testScores[i][0], 
                     &testScores[i][numScores + 1], answerKey))
         std::cout << "Student has all right answers for key 1\n";
      else
         std::cout << "Student does not have all right answers for key 1\n";
   }

   for (int i = 0; i < numStudents; ++i)
   {
      if (std::equal(&testScores[i][0], 
                     &testScores[i][numScores + 1], answerKey2))
         std::cout << "Student has all right answers for key 2\n";
      else
         std::cout << "Student does not have all right answers for key 2\n";
   }
}

輸出：

Student has all right answers for key 1
Student does not have all right answers for key 2