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在SQL中將數字拆分為范圍

[英]Split number to ranges in SQL

我正在嘗試編寫一個SQL查詢來顯示自2015年1月31日以來客戶資歷的分布情況:

  1. 長達一個月
  2. 一到六個月
  3. 六個月至一年之間
  4. 一年多

我成功地將客戶的月數進行了分組。

SELECT Seniority, COUNT(Customer_ID) [Number of Customers]
FROM
(SELECT Customer_ID,
DATEDIFF(MONTH, MIN(CONVERT(datetime, Order_Date)), '2015/01/31') Seniority
FROM Orders
GROUP BY Customer_ID) t
GROUP BY Seniority

在此處輸入圖片說明

如何按給定范圍划分?

預期:

        Seniorty                |   Number of Customers
Up to one month                 |            0
Between one and six months      |            14
Between six months and one year |            1
Over a year                     |            0

使用條件聚合:

WITH cte AS (
    SELECT
        'Up to one month' AS Seniority,
        COUNT(CASE WHEN DATEDIFF(MONTH, Order_Date, '2015-01-31') < 1 THEN 1 END) AS [Number of Customers],
        1 AS position
    FROM Orders
    UNION ALL
    SELECT
        'Between one and six months',
        COUNT(CASE WHEN DATEDIFF(MONTH, Order_Date, '2015-01-31') >= 1 AND
                        DATEDIFF(MONTH, Order_Date, '2015-01-31') < 6 THEN 1 END),
        2
    FROM Orders
    UNION ALL
    SELECT
        'Between six months and one year',
         COUNT( CASE WHEN DATEDIFF(MONTH, Order_Date, '2015-01-31') >= 6 AND
                        DATEDIFF(MONTH, Order_Date, '2015-01-31') < 12 THEN 1 END),
         3
    FROM Orders
    UNION ALL
    SELECT
        'Over a year',
        COUNT(CASE WHEN DATEDIFF(MONTH, Order_Date, '2015-01-31') > 12 THEN 1 END),
        4
    FROM Orders
)

SELECT
    Seniority,
    [Number of Customers]
FROM cte
ORDER BY
    position;

該答案假定Order_Date列已經是日期或日期時間。 如果不是,那么您應該做的第一件事就是將該列轉換為實際的日期類型。

WITH CTE AS (
    SELECT CUSTOMER_ID,
           CASE WHEN DATEDIFF(MONTH,'2015-01-31',ORDER_DATE)=1 THEN 'Up to one month'
               WHEN DATEDIFF(MONTH,'2015-01-31',ORDER_DATE) BETWEEN 1 AND 6 THEN 'Between one and six months'
               WHEN DATEDIFF(MONTH,'2015-01-31',ORDER_DATE) BETWEEN 6 AND 12 THEN 'Between six months and one year'
               WHEN DATEDIFF(MONTH,'2015-01-31',ORDER_DATE)>12 THEN 'Over a year'
           END AS SENIORITY
      FROM ORDERS 
     )
SELECT SENIORITY AS 'Seniority', COUNT(CUSTOMER_ID) AS 'Number of Customers'
FROM CTE
WHERE SENIORITY IS NOT NULL
GROUP BY SENIORITY

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