[英]Subtracting value from previous row sql by group
我有以下數據集:
DATA_FIM CENTRO C M ESTOQUE
2018-02-01 HD01 CD 70 539.000
2018-03-01 HD01 CD 70 511.000
2018-04-01 HD01 CD 70 468.000
2018-05-01 HD01 CD 70 447.000
2018-06-01 HD01 CD 70 382.000
2018-07-01 HD01 CD 70 348.000
2018-08-01 HD01 CD 70 285.000
2018-09-01 HD01 CD 70 245.000
2018-10-01 HD01 CD 70 221.000
2018-11-01 HD01 CD 70 207.000
2018-12-01 HD01 CD 70 122.000
2018-12-21 HD01 CD 70 101.000
2018-02-01 HD01 CD 71 164.000
2018-03-01 HD01 CD 71 147.000
2018-04-01 HD01 CD 71 124.000
2018-05-01 HD01 CD 71 107.000
2018-06-01 HD01 CD 71 78.000
1-以第二,第三,第四列為一組,我想從同一列的上一行中減去第五列的值。
為了創建一個新行。
[![數據] [2]] [2]
這個問題非常相似:[問題:13196190] [3],但是,在我的情況下,我有多個索引,並且不確定如何解決。
我正在使用建議的代碼
select
ZBI_FAT_PRODUCT.DATA_FIM,
ZBI_DIM_EMPRESA.CENTRO,
ZBI_DIM_EMPRESA.CANAL,
ZBI_DIM_PRODUCT.MATERIAL,
ZBI_DIM_PRODUCT.TITULO,
ZBI_FAT_PRODUCT.ESTOQUE_VENDA,
LAG(ZBI_FAT_PRODUCT.ESTOQUE_VENDA, 1, ZBI_FAT_PRODUCT.ESTOQUE_VENDA) OVER (PARTITION BY ZBI_DIM_EMPRESA.CENTRO, ZBI_DIM_PRODUCT.MATERIAL, ZBI_DIM_PRODUCT.TITULO ORDER BY ZBI_FAT_PRODUCT.DATA_FIM) - ZBI_FAT_PRODUCT.ESTOQUE_VENDA AS NEW
FROM ZBI_DIM_EMPRESA INNER JOIN (ZBI_DIM_PRODUCT INNER JOIN ZBI_FAT_PRODUCT ON ZBI_DIM_PRODUCT.BK = ZBI_FAT_PRODUCT.BK_MATERIAL) ON ZBI_DIM_EMPRESA.BK = ZBI_FAT_PRODUCT.BK_EMPRESA;
您似乎只想要lag()
:
select el.*,
(lag(estoque, 0, estoque) over (partition by centro, c, m order by date_mif) -
estoque
) as diff
from energylog el;
編輯:
對於已編輯的問題,似乎只有兩列組成一個組
select el.*,
(lag(estoque, 0, value) over (partition by centro, canal, order by date_mif) -
estoque
) as diff
from energylog el;
為簡便起見,並從評論中提取解決方案-
答案是使用LAG()
函數:
SELECT *,
LAG(ESTOQUE, 1, ESTOQUE) OVER (PARTITION BY CENTRO, C, M ORDER BY DATA_FIM) - ESTOQUE AS New
FROM EnergyLog
這是此工作的示例: SQLFiddle
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