postgres SQL查詢在節點JS中拋出錯誤

Question

我設置了一個API，在客戶端用戶可以計算到點之間的路由。 但是，我遇到了psql查詢的麻煩，它在postgres中工作，但是當我在節點JS中使用相同的查詢時，我收到了一個錯誤。

我正在使用nodeJS，Express和Postgres。 如果我在pgAdmin4中運行下面的查詢，我會得到預期的輸出。

SELECT b.gid, b.the_geom, b.cost_s, b.length_m FROM pgr_dijkstra('SELECT gid::bigint as id, source::bigint, 
                                           target::bigint, cost_s::double precision as cost, 
                                           reverse_cost_s::double precision as reverse_cost FROM ways 
                                           WHERE the_geom && ST_Expand((SELECT ST_Collect(the_geom) 
                                           FROM ways_vertices_pgr WHERE id IN(589143, 581050)), 0.01)', 
589143, 581050) a LEFT JOIN ways b ON (a.edge = b.gid);

但是當我在Node Js中使用相同的查詢（見下文）時，我收到一條錯誤消息，指出error: syntax error at or near "&&" 。 我究竟做錯了什么？

const start = parseInt(request.params.start)
const end = parseInt(request.params.end)

const sql2 = 
     "SELECT b.gid, b.the_geom, b.cost_s, b.length_m FROM pgr_dijkstra('SELECT gid::bigint as id, source::bigint,"+
     "target::bigint, cost_s::double precision as cost," +
     "reverse_cost_s::double precision as reverse_cost FROM ways" + 
     "WHERE the_geom && ST_Expand((SELECT ST_Collect(the_geom)" + 
     "FROM ways_vertices_pgr WHERE id IN(" + start + "," + end + ")), 0.01)'," +
      start + "," + end + ") a LEFT JOIN ways b ON (a.edge = b.gid);"

Answer 1

得到了答案。 我使用語法$1 ...而不是start和end ，並添加了參數的數據類型。 在我的情況下， ineteger

SELECT b.gid, b.the_geom, b.cost_s, b.length_m FROM pgr_dijkstra('SELECT gid::bigint as id, source::bigint, 
                                           target::bigint, cost_s::double precision as cost, 
                                           reverse_cost_s::double precision as reverse_cost FROM ways 
                                           WHERE the_geom && ST_Expand((SELECT ST_Collect(the_geom) 
                                           FROM ways_vertices_pgr WHERE id IN(' || $1::integer || ',' || $2::integer ||')), 0.01)', 
    $1::integer, $2::integer) a LEFT JOIN ways b ON (a.edge = b.gid);