如何從嵌套列表和字典中讀取字典鍵和值

Question

我有嵌套字典和列表的以下字典，試圖輸出所有鍵“名稱”的值。 我不知道要在這本字典上實現的邏輯

期望輸出像

test
inside_test
inner_group1
GetFTP

字典數據：

{
  "id": "0ce8df69-016b-1000-ffff-ffffbe50cb53",
  "name": "test",
  "processGroupStatusSnapshot": {
    "name": "test",
    "connectionStatusSnapshots": [],
    "processorStatusSnapshots": [],
    "processGroupStatusSnapshots": [
      {
        "id": "0ce90089-016b-1000-ffff-ffffadb84af5",
        "processGroupStatusSnapshot": {
          "name": "inside_test",
          "connectionStatusSnapshots": [],
          "processorStatusSnapshots": [],
          "processGroupStatusSnapshots": [
            {
              "id": "0ce97287-016b-1000-0000-000056414ae7",
              "processGroupStatusSnapshot": {
                "id": "0ce97287-016b-1000-0000-000056414ae7",
                "name": "inner_group1",
                "connectionStatusSnapshots": [],
                "processorStatusSnapshots": [
                  {
                    "id": "0ce9ca47-016b-1000-0000-0000496a342d",
                    "processorStatusSnapshot": {
                      "id": "0ce9ca47-016b-1000-0000-0000496a342d",
                      "groupId": "0ce97287-016b-1000-0000-000056414ae7",
                      "name": "GetFTP"
                    }
                  }
                ],
                "processGroupStatusSnapshots": [],
                "remoteProcessGroupStatusSnapshots": [],
                "inputPortStatusSnapshots": [],
                "outputPortStatusSnapshots": []
              }
            }
          ]
        }
      }
    ]
  }
}

Answer 1

考慮到嵌套，以及鍵名在所有級別上都將保持不變的事實，我認為遞歸解決方案將在此處最有效。 請隨時使用此解決方案作為參考，並根據需要進行修改。

參數d是這里的字典。

def find_name(d):
    if 'processGroupStatusSnapshot' in d:
        print("Name =", d['processGroupStatusSnapshot']['name'])
        nxt = d['processGroupStatusSnapshot']['processGroupStatusSnapshots']
        if len(nxt) > 0:
            find_name(nxt[0])

find_name(d)