[英]Regex: make 'zero or one time occurence' condition but only for the last match
我有這個字符串:
key1:val1;key2:val2;key3:val3
也可以這樣寫:
key1:val1;key2:val2;key3:val3;
我想要上面的兩個字符串都為preg_match_all,因此它將返回相同的數組,如下所示:
比賽1
Array
(
[0] => key1
[1] => key2
[2] => key3
)
比賽2
Array
(
[0] => val1
[1] => val2
[2] => val3
)
現在,我正在使用此正則表達式:
(.*?):(.*?);
不幸的是,它不適用於第一個字符串。 我之前嘗試過使用正則表達式,但結果更糟:
(.*?):(.*?);?
到目前為止,這是我的實驗: https : //3v4l.org/5HAco 。 如果有一個純PHP函數可以解決此問題,我也可以接受。
$text = "key1:val1;key2:val2;key3:val3";
preg_match_all("/(.*?):(.*?)(?:;|$)/",$text,$matches);
print_r($matches);
$text = "key1:val1;key2:val2;key3:val3;";
preg_match_all("/(.*?):(.*?)(?:;|$)/",$text,$matches);
print_r($matches);
輸出:
Array
(
[0] => Array
(
[0] => key1:val1;
[1] => key2:val2;
[2] => key3:val3
)
[1] => Array
(
[0] => key1
[1] => key2
[2] => key3
)
[2] => Array
(
[0] => val1
[1] => val2
[2] => val3
)
)
Array
(
[0] => Array
(
[0] => key1:val1;
[1] => key2:val2;
[2] => key3:val3;
)
[1] => Array
(
[0] => key1
[1] => key2
[2] => key3
)
[2] => Array
(
[0] => val1
[1] => val2
[2] => val3
)
)
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