打印出以's'開頭的單詞時，我的jupyter筆記本沒有響應是代碼錯誤還是筆記本問題？

Question

在運行代碼以's'開頭的單詞的打印過程中，jupyter筆記本沒有響應

st = 'Print only the words that start with s in this s'
lis=st.split()
i=0
res=[]
while i<len(lis):
    if lis[i][0]=='s':
        res.append(list[i])
        i+=1
print(res)

Answer 1

如果列表中的第一個單詞不是以s開頭，則您的代碼將卡住，將i的增量更改為if，如下所示：

st = 'Print only the words that start with s in this s'
lis=st.split()
i=0
res=[]
while i<len(lis):
    if lis[i][0]=='s':
        res.append(list[i])
    i+=1
print(res)

編輯：此代碼的改進的版本

st = 'Print only the words that start with s in this s'
res=[]
for s in st.split():
    if s[0] == 's':
        res.append(s)

print(res)

您還可以使用列表理解

st = 'Print only the words that start with s in this s'
res = [s for s in st.split() if s[0] == 's']
print(res)
# prints ['start', 's', 's']

Answer 2

您可以像下面這樣以更Python的方式嘗試它：

st = 'Print only the words that start with s in this s' 
lis=st.split()
results = []
for word in lis:
    if word.startswith("s"):
        results.append(word)
print(results)

O / P：

['start', 's', 's']

Answer 3

在這種情況下，for循環更好。 拆分字符串時，將獲得單詞列表。 使用for代替while。

st = 'Print only the words that start with s in this s'
lis=st.split()
res=[]
for word in lis:
    if(word.startswith("s")):
        res.append(word)

Answer 4

您正在使用i來跟蹤計數（ i=0 ）和可迭代變量（ if lis[i][0]=='s' ）

我建議使用枚舉來跟蹤計數

st = 'Print only the words that start with s in this s'
lis=st.split()
res=[]

for c, i in enumerate(lis):
    if i[0] == 's': # here, you can also use i[0].lower() if you want to count words that might start with a capital 's'
        res.append(i)

print(c) # keep track of the number of things being iterated over
print(res) # the list of items starting with s
print(len(res)) # how many items starting with s

編輯：在問題編輯之前回答。