合並查詢（WQL子選擇查詢-Powershell-SCCM）

Question

現在，我正在使用兩個不同的查詢並比較生成的對象，但是我更希望使用一個唯一的查詢來完成所有需要的操作，因為我希望直接在SCCM中使用它，而不僅僅是PowerShell。

（第一個查詢將創建一個對象，其中包含已安裝某些x64軟件的所有計算機，第二個對象將創建一個查詢，其中包含未安裝某些x86軟件的所有計算機）

比較這兩個對象，就可以得到所需的列表（兩個對象中都有哪些機器）

但是，我將如何結合這兩個查詢，使它們全部合而為一？

如：

所有具有SMS_G_System_ADD_REMOVE_PROGRAMS_64.DisplayName =“ SOFTWARE1”並且沒有SMS_G_System_ADD_REMOVE_PROGRAMS.DisplayName =“ SOFTWARE2”的計算機

$SiteCode = "x"
$SiteServer = "x"

$query = @"

select *  from  SMS_R_System 
inner join SMS_G_System_ADD_REMOVE_PROGRAMS_64 
on SMS_G_System_ADD_REMOVE_PROGRAMS_64.ResourceId = SMS_R_System.ResourceId 
where SMS_G_System_ADD_REMOVE_PROGRAMS_64.DisplayName = "SOFTWARE1"
"@

$postes_xx = (Get-WmiObject -namespace root\sms\site_$SiteCode -computer $SiteServer -query $query).SMS_R_SYSTEM.Name


$query = @"

select SMS_R_SYSTEM.ResourceID,SMS_R_SYSTEM.ResourceType,SMS_R_SYSTEM.Name,SMS_R_SYSTEM.SMSUniqueIdentifier,SMS_R_SYSTEM.ResourceDomainORWorkgroup,SMS_R_SYSTEM.Client
from SMS_R_System 
inner join SMS_G_System_COMPUTER_SYSTEM 
on SMS_G_System_COMPUTER_SYSTEM.ResourceID = SMS_R_System.ResourceId 
where SMS_G_System_COMPUTER_SYSTEM.Name 
not in (select distinct SMS_G_System_COMPUTER_SYSTEM.Name 
       from  SMS_R_System
       inner join SMS_G_System_COMPUTER_SYSTEM
       on SMS_G_System_COMPUTER_SYSTEM.ResourceID = SMS_R_System.ResourceId
       inner join SMS_G_System_ADD_REMOVE_PROGRAMS
       on SMS_G_System_ADD_REMOVE_PROGRAMS.ResourceID = SMS_R_System.ResourceId
       where SMS_G_System_ADD_REMOVE_PROGRAMS.DisplayName = "SOFTWARE2" )

"@


$postes_32x = Get-WmiObject -namespace root\sms\site_$SiteCode -computer $SiteServer -query $query | select -ExpandProperty name

Compare-Object $postes_xx $postes_x32 -IncludeEqual -ExcludeDifferent

Answer 1

似乎您可以只包括所有聯接，然后將where語句與and組合在一起。 您將需要調整select語句以包含您關心的列。

$query = @"

select *  from  SMS_R_System 
inner join SMS_G_System_ADD_REMOVE_PROGRAMS_64 
on SMS_G_System_ADD_REMOVE_PROGRAMS_64.ResourceId = SMS_R_System.ResourceId 
inner join SMS_G_System_COMPUTER_SYSTEM 
on SMS_G_System_COMPUTER_SYSTEM.ResourceID = SMS_R_System.ResourceId 
where (SMS_G_System_ADD_REMOVE_PROGRAMS_64.DisplayName = "SOFTWARE1")
and (SMS_G_System_COMPUTER_SYSTEM.Name 
not in (select distinct SMS_G_System_COMPUTER_SYSTEM.Name 
       from  SMS_R_System
       inner join SMS_G_System_COMPUTER_SYSTEM
       on SMS_G_System_COMPUTER_SYSTEM.ResourceID = SMS_R_System.ResourceId
       inner join SMS_G_System_ADD_REMOVE_PROGRAMS
       on SMS_G_System_ADD_REMOVE_PROGRAMS.ResourceID = SMS_R_System.ResourceId
       where SMS_G_System_ADD_REMOVE_PROGRAMS.DisplayName = "SOFTWARE2" ))

"@

Answer 2

似乎沒有必要使用SMS_G_System_Computer_System類。 這是應該滿足您要求的WQL的簡單版本。

select SMS_R_System.Name 
from SMS_R_System 
where SMS_R_System.ResourceID in 
(select SMS_G_System_ADD_REMOVE_PROGRAMS_64.ResourceID 
from SMS_G_System_ADD_REMOVE_PROGRAMS_64 
where SMS_G_System_ADD_REMOVE_PROGRAMS_64.DisplayName = "SOFTWARE1") 
and SMS_R_System.ResourceID not in 
(select SMS_G_System_ADD_REMOVE_PROGRAMS.ResourceID 
from SMS_G_System_ADD_REMOVE_PROGRAMS 
where SMS_G_System_ADD_REMOVE_PROGRAMS.DisplayName = "SOFTWARE2")

希望我的回答能對您有所幫助，並期待您的反饋。

最好的問候，雷