[英]Special Characters - Sql
如何在SqlServer的列中獲取特殊字符?
我收到了電子郵件列表,還必須找到特殊的角色,例如下面的波紋管
**Email**
JóhnSnow@gmail.com
Khãlessi@gmail.com
如您在上面看到的,有〜〜和' ´作為特殊字符 。 可能會出現其他字符,例如“ .. ”或其他字符。
我正在使用Sql Server 2012,
有人建議解決嗎?
要提取特殊字符,您首先需要將字符串分成幾行,以便可以分別查詢每個字符,您可以使用數字表進行查詢。 如果您沒有,則可以很容易地即時創建它們:
WITH N1 AS (SELECT N FROM (VALUES (1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) n (N)),
N2 (N) AS (SELECT 1 FROM N1 AS N1 CROSS JOIN N1 AS N2),
N3 (N) AS (SELECT 1 FROM N2 AS N1 CROSS JOIN N2 AS N2),
Numbers (Number) AS (SELECT ROW_NUMBER() OVER(ORDER BY N) FROM N3)
SELECT Number
FROM Numbers;
這給出了從1-10000的數字列表。 更多關於此這里 。
然后,您可以將其加入條件為Number < LEN(Email)
以確保為電子郵件中的每個字符返回上一行,然后使用SUBSTRING()
提取位置n
處的字符:
DECLARE @T TABLE (ID INT IDENTITY, Email NVARCHAR(255));
INSERT @T (Email)
VALUES (N'JóhnSnów@gmail.com'), (N'Khãlessi@gmail.com'), ('NedStark@gmail.com');
WITH N1 AS (SELECT N FROM (VALUES (1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) n (N)),
N2 (N) AS (SELECT 1 FROM N1 AS N1 CROSS JOIN N1 AS N2),
N3 (N) AS (SELECT 1 FROM N2 AS N1 CROSS JOIN N2 AS N2),
Numbers (Number) AS (SELECT ROW_NUMBER() OVER(ORDER BY N) FROM N3)
SELECT t.ID,
t.Email,
Character = SUBSTRING(t.Email, n.Number, 1)
FROM @T AS t
INNER JOIN Numbers n
ON n.Number < LEN(t.Email)
ORDER BY t.ID;
這使:
ID Email Character
-----------------------------
1 JóhnSnow@gmail.com J
1 JóhnSnow@gmail.com ó
1 JóhnSnow@gmail.com h
1 JóhnSnow@gmail.com n
1 JóhnSnow@gmail.com S
1 JóhnSnow@gmail.com n
1 JóhnSnow@gmail.com ó
1 JóhnSnow@gmail.com w
.....
然后,您可以通過使用排序SQL_Latin1_General_Cp1251_CS_AS
將特殊字符轉換為VARCHAR
並將其檢查為原始字符來提取特殊字符:
DECLARE @T TABLE (ID INT IDENTITY, Email NVARCHAR(255));
INSERT @T (Email)
VALUES (N'JóhnSnów@gmail.com'), (N'Khãlessi@gmail.com'), ('NedStark@gmail.com');
WITH N1 AS (SELECT N FROM (VALUES (1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) n (N)),
N2 (N) AS (SELECT 1 FROM N1 AS N1 CROSS JOIN N1 AS N2),
N3 (N) AS (SELECT 1 FROM N2 AS N1 CROSS JOIN N2 AS N2),
Numbers (Number) AS (SELECT ROW_NUMBER() OVER(ORDER BY N) FROM N3),
AllCharacters as
( SELECT t.ID,
t.Email,
Character = SUBSTRING(t.Email, n.Number, 1),
Position = n.Number
FROM @T AS t
INNER JOIN Numbers n
ON n.Number < LEN(t.Email)
)
SELECT ac.ID, ac.Character, ac.Position
FROM AllCharacters AS ac
WHERE CONVERT(CHAR(1), ac.Character) COLLATE SQL_Latin1_General_Cp1251_CS_AS <> ac.Character
ORDER BY ac.ID;
結果
ID Email Character Position
----------------------------------------------------
1 JóhnSnów@gmail.com ó 2
1 JóhnSnów@gmail.com ó 7
2 Khãlessi@gmail.com ã 3
最后,如果需要,您可以使用XML擴展將這些字符連接到單個列中:
DECLARE @T TABLE (ID INT IDENTITY, Email NVARCHAR(255));
INSERT @T (Email)
VALUES (N'JóhnSnów@gmail.com'), (N'Khãlessi@gmail.com'), ('NedStark@gmail.com');
WITH N1 AS (SELECT N FROM (VALUES (1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) n (N)),
N2 (N) AS (SELECT 1 FROM N1 AS N1 CROSS JOIN N1 AS N2),
N3 (N) AS (SELECT 1 FROM N2 AS N1 CROSS JOIN N2 AS N2),
Numbers (Number) AS (SELECT ROW_NUMBER() OVER(ORDER BY N) FROM N3),
AllCharacters as
( SELECT t.ID,
t.Email,
Character = SUBSTRING(t.Email, n.Number, 1),
Position = n.Number
FROM @T AS t
INNER JOIN Numbers n
ON n.Number < LEN(t.Email)
), SpecialCharacters AS
( SELECT ac.ID, ac.Character, ac.Position
FROM AllCharacters AS ac
WHERE CONVERT(CHAR(1), ac.Character) COLLATE SQL_Latin1_General_Cp1251_CS_AS <> ac.Character
)
SELECT t.ID,
t.Email,
SpecialCharacters = ISNULL(STUFF(s.SpecialCharacterList.value('.', 'NVARCHAR(255)'), 1, 2, ''), '')
FROM @T AS T
CROSS APPLY
( SELECT CONCAT(N', ', s.Character, '(', Position, ')')
FROM SpecialCharacters AS s
WHERE s.ID = t.ID
ORDER BY Position
FOR XML PATH(''), TYPE
) s (SpecialCharacterList)
ORDER BY ID;
結果
ID Email SpecialCharacters
------------------------------------------------
1 JóhnSnów@gmail.com ó(2), ó(7)
2 Khãlessi@gmail.com ã(3)
3 NedStark@gmail.com
順便說一句,它可能更適合於您在表中存儲算作特殊字符的需求,而不是依賴於代碼頁進行特定的校對,如果您要這樣做,則只需要更改以下行即可:
WHERE CONVERT(CHAR(1), ac.Character) COLLATE SQL_Latin1_General_Cp1251_CS_AS <> ac.Character
對於:
WHERE EXISTS (SELECT 1 FROM MySpecialCharacterTable AS sct WHERE sct.Character = ac.Character)
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