C ++字符串數組在20字節后拆分

Question

我有這個代碼示例，用於制作最終將通過BLE發送的20字節大小的數據包。 我想更改代碼，以便輸入我的數據數組（加速度計讀數）。

我的數據：

float ax, ay, az, gx, gy, gz, mx, my, mz, yaw, pitch, roll;
char myConcatenation[80];
sprintf(myConcatenation, "%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f", ax,  ay, az, gx, gy, gz, mx, my, mz, yaw, pitch, roll);

功能定義：

std::vector<std::string> buildPackets(std::string data, size_t packetSize) {
  // split up the packet
  size_t partialPacketSize = packetSize - 4;

  // calculate how many packets
  size_t packetCount = data.length() / partialPacketSize;
  packetCount = data.length() % partialPacketSize == 0 ? packetCount : packetCount + 1;

  std::vector<std::string> packets;
  // construct each packet
  for (int i = 0; i < packetCount; i++) {
    // start of packet
    std::string packet = "##";
    packet += (char)packetCount;
    packet += (char)(i + 1);
    std::string part = i == packetCount - 1 ? data.substr(i * partialPacketSize) : data.substr(i * partialPacketSize, partialPacketSize);
    packet.append(part);

    // add to vector of packets
    packets.push_back(packet);
  }

函數調用：這里的變量data是字符串，我需要的就是放在myConcatenation[]

我應該在代碼中進行哪些更改才能使其正常工作？

   std::string data = "averylongstringofdatathatislargerthantwentycharacters";
size_t chars = data.length();
size_t packetSize = 20;

// assume I have this characteristic already setup
if (chars > packetSize) {
  auto packets = buildPackets(data, packetSize);
  for (auto packet : packets) {
    txCharacteristic->setValue(packet);
    txCharacteristic->notify();
  }
}
else {
  txCharacteristic->setValue(data);
  txCharacteristic->notify();
}

感謝您的任何幫助。

---

編輯：

this is what I have now: 

std::vector<std::string> buildPackets(std::string data, size_t packetSize) {
  // split up the packet
  size_t partialPacketSize = packetSize - 4;

  // calculate how many packets
  size_t packetCount = data.length() / partialPacketSize;
  packetCount = data.length() % partialPacketSize == 0 ? packetCount : packetCount + 1;

  std::vector<std::string> packets;
  // construct each packet
  for (int i = 0; i < packetCount; i++) {
    // start of packet
    std::string packet = "@";
    packet += (char)packetCount;
    packet += (char)(i + 1);
    std::string part = i == packetCount - 1 ? data.substr(i * partialPacketSize) : data.substr(i * partialPacketSize, partialPacketSize);
    packet.append(part);

    // add to vector of packets
    packets.push_back(packet);
  }

  return packets;
}


--------
**call function**

sprintf(myConcatenation, "#%3.2f,%3.2f,%3.2f,#%3.2f,%3.2f,%3.2f,#%3.2f,%3.2f,%3.2f,#%3.2f,%3.2f,%3.2f", ax,  ay, az, gx, gy, gz, mx, my, mz, yaw, pitch, roll);

size_t packetSize = 20;

auto packets = buildPackets(myConcatenation, packetSize);
  for (auto packet : packets) {
    pCharacteristic->setValue(packet);
    pCharacteristic->notify();
  }

  Serial.println(myConcatenation);

---

我可以問你接收方嗎？ 我的字符串在每個不同傳感器讀數的開頭都有# （＃ax，ay，az，＃gx，gy ...）和@在每個數據包的開頭。 你知道應該如何實現接收方（我在MITAppInventor中這樣做但我想不出如何按順序連接數據包並將它們附加到.csv文件中。（每列=不同的數據）。

謝謝！

Answer 1

String類提供了一個構造函數，它接受輸入const char *，因此您可以使用它將您的變量命名數據（隱式或顯式）轉換為std :: string。

所以最后，只需將其傳遞給函數即可

float ax, ay, az, gx, gy, gz, mx, my, mz, yaw, pitch, roll; char myConcatenation[80]; sprintf(myConcatenation, "%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f,%3.2f", ax, ay, az, gx, gy, gz, mx, my, mz, yaw, pitch, roll); auto packets = buildPackets(myConcatenation, packetSize);

就這樣。

一個快速的額外建議：

• 用sprintf_s改變sprintf，它更安全

字符串引用