在PHP中合並兩個JSON數組

Question

我需要在PHP中合並兩個json文件。 一個是空的，另一個是每次通話都會改變。

我發現很多代碼在PHP中將兩個JSON數組合並為一個，但它對我不起作用。

$final_array = array();
$first_json = file_get_contents("test3.json");
$second_json = file_get_contents("my-file.json");


if(json_decode($first_json,true) == null){
    $final_array[] = json_decode($second_json,true);
    $merge_final_array = json_encode(json_decode($second_json,true));
}else{
    $final_array[] = json_decode($first_json,true);
    $final_array[] = json_decode($second_json,true);
    $merge_final_array = json_encode($final_array);
}

file_put_contents("test3.json", $merge_final_array);
$merge_final_array = null;

我遞歸地向“test3.json”文件添加了我在“my-file.json”中找到的數據。

這應該給我：

[{"score":15,"win":true,"device":"Android SDK built for x86"},{"score":"Finish","device":"Android SDK built for x86","win":true},{"win":true,"score":"Finish","device":"Android SDK built for x86"},{"score":16,"scenario":"Finish","win":true,"device":"Android SDK built for x86"}]

因為它給了我：

[[[{"score":15,"win":true,"device":"Android SDK built for x86"},{"score":"Finish","device":"Android SDK built for x86","win":true}],{"win":true,"score":"Finish","device":"Android SDK built for x86"}],{"score":16,"scenario":"Finish","win":true,"device":"Android SDK built for x86"}]

我也嘗試了json_encode(array_merge(json_decode($first_json, true),json_decode($second_json, true)))方法json_encode(array_merge(json_decode($first_json, true),json_decode($second_json, true)))它給了我： 代碼+結果

我做錯了什么？

Answer 1

您首先需要將JSON轉換為數組，然后才能在PHP執行任何操作。

首先，您需要在PHP創建一個新的空數組，並將JSON數組添加到該空數組中。
然后再將數組編​​碼為JSON並將其寫入文件。
您的完整代碼：

$first_json = file_get_contents("test3.json");
$second_json = file_get_contents("my-file.json");

$first_array = json_decode($first_json, true); // make array of json
$second_array = json_decode($second_json, true); // make array of json

$final_array = array(); // create an empty array 
$final_array[] = $first_array; // add first array to empty array
$final_array[] = $second_array;  // add second array to array

$final_json = json_encode($final_array); // make a json from the array again

file_put_contents("test3.json", $final_json); // put the json inside a new file 

Answer 2

這是你想要的：

<?php

$finalArray = [];

// file_get_contents("test3.json");
$firstFileContent = '{"score":15,"win":true,"device":"Android SDK built for x86"}';

// file_get_contents("my-file.json")
$secondFileContent = '{"score":"Finish","device":"Android SDK built for x86","win":true}';

$firstJson = json_decode($firstFileContent, true);
if(JSON_ERROR_NONE === json_last_error()){
    $finalArray[] = $firstJson;
}

$finalArray[] = json_decode($secondFileContent, true);

$finalJson = json_encode($finalArray);

http://sandbox.onlinephpfunctions.com/code/404972fb59b4f7323f81ee444a1cb14f772f7748

它給了我這個： 代碼+結果

這都是因為你做了兩個數組的array_merge而第二個將重寫第一個值。 您應該將第二個數組添加到結果數組，而不是合並。

array_merge(["a" => 1], ["a" => 2]) // result: ["a" => 2]

$result[] = ["a" => 1];
$result[] = ["a" => 2];
// result: [["a" => 1], ["a" => 2]]

json_encode（array_merge（json_decode（$ first_json，true），json_decode（$ second_json，true）））

這不起作用，因為在每個文件中您都有編碼對象 ，而不是對象數組。 如果你有第一個文件{"a":1}和第二個文件{"a":2} ，當你合並他們的解碼值時，結果將是{"a":2} ，但如果你有將它們編輯為[{"a": 1}]和[{"a": 2}] ，結果將是[{"a": 1}, {"a": 2}]因為現在要合並轉換為數組的對象數組，而不是對象。

---

如果要以遞歸方式從兩個文件中添加數據，則應執行以下操作：

<?php

$finalArray = [];

$firstFileContent = '[[{"score":15,"win":true,"device":"Android SDK built for x86"},{"score":"Finish","device":"Android SDK built for x86","win":true}],{"win":true,"score":"Finish","device":"Android SDK built for x86"}]';
$secondFileContent = '{"score":16,"scenario":"Finish","win":true,"device":"Android SDK built for x86"}';

mergeJsonRecursively($finalArray, $firstFileContent);
mergeJsonRecursively($finalArray, $secondFileContent);

function mergeJsonRecursively(array &$result, string $json)
{
    $decodedJson = json_decode($json);
    if (JSON_ERROR_NONE === json_last_error()) {
        tryToAddElementToResult($result, $decodedJson);

        if (is_array($decodedJson)) {
            foreach ($decodedJson as $element) {
                tryToAddElementToResult($result, $element);

                if (is_array($element)) {
                    mergeJsonRecursively($result, json_encode($element));
                }
            }
        }
    }
}

function tryToAddElementToResult(array &$result, $element)
{
    if (is_object($element)) {
        $result[] = json_decode(json_encode($element), true);
    }
}

$finalJson = json_encode($finalArray);

http://sandbox.onlinephpfunctions.com/code/f4858bcc87da34e4ee6639b2ee96c7ac3244ae1b

你會給出預期的結果：

[{"score":15,"win":true,"device":"Android SDK built for x86"},{"score":"Finish","device":"Android SDK built for x86","win":true},{"win":true,"score":"Finish","device":"Android SDK built for x86"},{"score":16,"scenario":"Finish","win":true,"device":"Android SDK built for x86"}]

Answer 3

只是這樣做。 您可以添加自己的錯誤處理，但基本應該是：

$final_array = array();
$first_json = file_get_contents("test3.json");
$second_json = file_get_contents("my-file.json");

$first_array = json_decode($first_json,true);
$second_array = json_decode($second_json,true);

if(is_array($first_array) and is_array(second_array)){
    $final_array = array_merge(first_array,second_array);
}
else if(!empty($first_array) and is_array($first_array)){
    $final_array = $first_array;
}
else if(!empty(second_array) and is_array(second_array)){
    $final_array = second_array;
}

$final_json = json_encode(final_array);

file_put_contents("test3.json", final_json);