/ bin / sh：1：未找到觸摸

Question

當使用command = touch aaa傳遞時，下面的代碼可能會出現什么問題

它拋出/bin/sh: 1: touch aaa: not found

這是代碼

boolean isWindows = System.getProperty("os.name")
        .toLowerCase().startsWith("windows");
String [] cmd ={"-c", command};
CommandLine cmdLine = new CommandLine("/bin/sh");
cmdLine.addArguments( cmd,false );
if (isWindows) {
    DefaultExecutor exec = new DefaultExecutor();
    exec.setExitValue(0);
    exec.setWorkingDirectory(new File(System.getProperty("user.home")));
    int exitCode = exec.execute(cmdLine);
    return new Response(exitCode, "");

} else {
    DefaultExecutor exec = new DefaultExecutor();
    exec.setExitValue(0);
    exec.setWorkingDirectory(new File(System.getenv("HOME")));
    int exitCode = exec.execute(cmdLine);
    return new Response(exitCode, "");
}

Answer 1

你確定touch和aaa之間有一個合適的空間（0x20）嗎？

當您嘗試使用參數從sh運行不存在的命令時，shell中的“未找到”消息不包含參數：

% sh -c 'touchx aaa'        
sh: 1: touchx: not found
% dash -c 'touchx aaa'      
dash: 1: touchx: not found
% bash -c 'touchx aaa'
bash: touchx: command not found
% busybox sh -c 'touchx aaa'
sh: touchx: not found

嘗試從命令行運行命令，不使用Java代碼，並查看它是否可以從那里運行。